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2 years ago

Can someone please help me on this?

Physics

1 answer:

Rashid [163]2 years ago

8 0

Don’t listen to the link the other person sent!!!

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A 10.0-kg box starts at rest and slides 3.5 m down a ramp inclined at an angle of 10° with the horizontal. If there is no fricti

Alenkinab [10]

Answer:

$v_f = 3.45 m/s$

Explanation:

As we know that box was initially at rest

so here work done by all forces on the box = change in its kinetic energy

so we will have

$mg sin\theta L = \frac{1}{2}mv_f^2 - \frac{1}{2}mv_i^2$

now we have

m = 10 kg

$\theta = 10^0$

L = 3.5 m

so we will have

$10(9.81)sin10 \times 3.5 = \frac{1}{2}(10)(v_f^2 - 0)$

$2(9.81) sin10 \times 3.5 = v_f^2$

so final speed is given as

$v_f = 3.45 m/s$

6 0

2 years ago

Help<br> help<br> help<br> plsssssssss

Aliun [14]

Elements to the left tend to form positive ions is the right answer mark me brainlist

4 0

2 years ago

A cyclist is coasting at 15 m/s when she starts down a 450 m long slope that is 30 m high. The cyclist and her bicycle have a co

Flura [38]

Answer:

Her speed at the bottom of the slope is 25.665 m/s

Explanation:

Here we have

Initial velocity, v₁= 15 m/s

Final velocity = v₂

The energy balance present in the system can be represented as

$\frac{1}{2}mv_2^2 -\frac{1}{2}mv_1^2 - mgh = W$

Where:

m = Mass of the cyclist = 70 kg

W = work done by the drag force = $-F_Dd$

Where:

d = Distance traveled = 450 m

Therefore,

$\frac{1}{2}mv_2^2 -\frac{1}{2}mv_1^2 - mgh = -F_Dd$ and

$v_2^2 =\frac{ \frac{1}{2}mv_1^2 + mgh -F_Dd}{ \frac{1}{2}m} = v_1^2 + 2gh -\frac{ 2F_Dd}{ m} = 15^2 + 2\times 9.8\times 30 - \frac{2\times 12\times 450}{70}$

= 658.714 m²/s²

v₂ = 25.665 m/s

Her speed at the bottom of the slope = 25.665 m/s.

6 0

2 years ago

When describing electromagnetic radiation, there is a(n) _____________ relationship between wavelength and frequency and the gre

ololo11 [35]

Correct option is (C) inverse ; more

8 0

2 years ago

Read 2 more answers

El cuerpo de una persona está cubierto con 1.6 m2 de ropa de lana. El grosor de la lana es 2.0 x 10-3 metro. La temperatura en l

netineya [11]

Answer:

<h2>Rate of heat transfer from the body of the person is given as</h2><h2> $\frac{dQ}{dt} = 800 J/s$ </h2>

Explanation:

As we know that the rate of heat transfer due to thermal conduction is given as

$\frac{dQ}{dt} = \frac{kA(T_2 - T_1)}{x}$

so we have

k = 0.04 W/m C

$A = 1.6 m^2$

$x = 2\times 10^{-3} m$

$\frac{dQ}{dt} = \frac{(0.04)(1.6)(36 - 11)}{2 \times 10^{-3}}$

$\frac{dQ}{dt} = 800 J/s$

8 0

2 years ago