Answer:
<h3>A. Dalton recognized that tiny atoms combined to form complex structures. </h3>
Answer:
The concentration of the NaOH solution CB = 0.251 M
Explanation:
The balanced equation of reaction is:
H2SO4 + 2NaOH ===> Na2SO4 + 2H2O
Using titration equation of formula
CAVA/CBVB = NA/NB
Where NA is the number of mole of acid = 1 (from the balanced equation of reaction)
NB is the number of mole of base = 2 (from the balanced equation of reaction)
CA is the concentration of acid = 0.1053 M
CB is the concentration of base = to be calculated
VA is the volume of acid = 17.88 mL
VB is the volume of base = 15.00mL
Substituting
0.1053×17.88/CB×15 = 1/2
Therefore CB =0.1053×17.88×2/15×1
CB= 0.251 M
Answer:
D is the correct answer.
Explanation:
I took the test on A pex. Everyone make sure you look at your answers. They are NOT always in the same order.
Answer:
Mole percent of water in azeotrope is 69%
Explanation:
Clearly, the azeotrope consists of water and perchloric acid.
So, 72% perchloric acid by mass means 100 g of azeotrope contains 72 g of perchloric acid and 28 g of water.
Molar mass of water = 18.02 g/mol and molar mass of perchloric acid = 100.46 g/mol
So, 72 g of perchloric acid = 
of perchloric acid = 0.72 mol of perchloric acid
Also, 28 g of water = 
of water = 1.6 mol of water
Hence total number of mol in azeotrope = (1.6+0.72) mol = 2.32 mol of azeotrope
So, mole percent of water in azeotrope = [(moles of water)/(total no of moles)]
%
Mole percent of water = 
% = 69%
