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2 years ago

10

The table shows data for two groups of plants one grown with fertilizer and the other without fetalizer was the mean height of t

he plant given fertilizer what affect does the vaule 35.6 have on the measures of central tendency for the data in the left column
A. The mean will be higher than the mode but lower then the median.

B. The mean will be lower than the median and the mode

C. The mean will be higher than the median but lower than the mode

D. The mean will be higher than the median and the mode

1 answer:

Dmitrij [34]2 years ago

8 0

Answer:

D is the correct answer.

Explanation:

I took the test on A pex. Everyone make sure you look at your answers. They are NOT always in the same order.

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2 years ago

My professor gave me two questions to solve using the Van Der Waals Equation. She told us to solve for P and the second one we h

Fed [463]

Answer:

P=atm

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Explanation:

The problem give you the Van Der Waals equation:

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First we are going to solve for P:

$(P+\frac{n^{2}a}{V^{2}})=\frac{nRT}{(V-nb)}$

$P=\frac{nRT}{(V-nb)}-\frac{n^{2}a}{v^{2}}$

Then you should know all the units of each term of the equation, that is:

$P=atm$

$n=mol$

$R=\frac{L.atm}{mol.K}$

$a=atm\frac{L^{2}}{mol^{2}}$

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$T=K$

$V=L$

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Now, you should replace the units in the equation for each value:

$P=\frac{(mol)(\frac{L.atm}{mol.K})(K)}{L-(mol)(\frac{L}{mol})}-\frac{(mol^{2})(\frac{atm.L^{2}}{mol^{2}})}{L^{2}}$

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$P=\frac{L.atm}{L-L}-atm$

Then operate the fraction subtraction:

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$P=\frac{L.atm}{L}$

And finally you can find the answer:

P=atm

Now solving for b:

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$nb=V-\frac{nRT}{(P+\frac{n^{2}a}{V^{2}})}$

$b=\frac{V-\frac{nRT}{(P+\frac{n^{2}a}{V^{2}})}}{n}$

Replacing units:

$b=\frac{L-\frac{(mol).(\frac{L.atm}{mol.K}).K}{(atm+\frac{mol^{2}.\frac{atm.L^{2}}{mol^{2}}}{L^{2}})}}{mol}$

Multiplying and dividing units,(please see the second photo below), we have:

$b=\frac{L-\frac{L.atm}{atm}}{mol}$

$b=\frac{L-L}{mol}$

$b=\frac{L}{mol}$

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