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Lera25 [3.4K]
3 years ago
9

Figure RST is reflected about the x-axis and then translated down 1 unit to obtain figure R’S’T’:Which statement best describes

the relationship between the two figures?
Figure RST is congruent to figure R’S’T’.
Figure RST is bigger than figure R’S’T’.
The measure of angle R is equal to the measure of angle S’.
The measure of angle R is equal to the measure of angle T’.

Mathematics
1 answer:
stepan [7]3 years ago
6 0

h.........

....................,...,........

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The population of camden, New Jersey has been decreasing by 0.12% a year on average. If this trend continues, and the population
Talja [164]
By the trend that is being given above, the population of New Jersey will only be 99.88% of the population from the previous year. It may be calculated through the following equation,
                               P(n) = P(0) x (1 - r)^n
Substituting the values from the given above,
                                  P(n) = 79,318 x (0.9988)^(2015 - 2006)
                                          = 78465.47
Thus, the population will approximately be 78,466. 
4 0
3 years ago
Ben works for software company in Cleveland. To train new employees, Ben travels to their two other locations, Buffalo and Phila
Andru [333]

Answer:

Explanation:we will solve this question with help of linear programming.

Now,  let Ben goes x times in buffalo trip and goes y times in Philadelphia trip. Thus, according to the question, Min Z= 180x+300y

And s.t.r. 2x+3y≤105, where x≥5, y≥15.

since at (0,0) 0≤105(true), so area of 2x+3y≤105 will cover the origin.

But, 0≥5 and 0≥15 are false, so their area will not cover the origin.

Thus, after drawing the graph of these three lines we will get a feasible reason of triangle ABC, where point A≡(5,31.667), B≡(5,15), and C≡(30,15)

Z at A- 180×5+300×31.667=10,400.1

at B-180×5+300×15=1350( which is minimum.)

at C- 180×30+300×15=5,850

Thus, Ben should go 5 times to buffalo trip and 15 times to Philadelphia to minimize his cost which is $1350.




3 0
4 years ago
PLZ help! Find the surface area and volume. Leave your answers in terms of TT.
Butoxors [25]
<h2><u>Solution</u>:-</h2>

1. Radius (r) of the sphere = 10 units. (Given)

• Surface area of the sphere = 4πr².

Surface area of the sphere = 4 × π × (10)²

Surface area of the sphere = 4 × π × 10 × 10

Surface area of the sphere = 400π units. (Ans)

And,

• Volume of the sphere = 4/3πr³.

Volume of the sphere = 4/3 × π × (10)³

Volume of the sphere = 4/3 × π × 10 × 10 × 10

Volume of the sphere = 4000π/3

Volume of the sphere = 1333.3π cubic units. [approx] (Ans)

__________________________________

2. Diameter of the sphere = 16 units. (Given)

Radius (r) of the sphere = 16/2 = 8 units.

• Surface area of the sphere = 4πr².

Surface area of the sphere = 4 × π × (8)²

Surface area of the sphere = 4 × π × 8 × 8

Surface area of the sphere = 256π units. (Ans)

And,

• Volume of the sphere = 4/3πr³.

Volume of the sphere = 4/3 × π × (8)³

Volume of the sphere = 4/3 × π × 8 × 8 × 8

Volume of the sphere = 2048π/3

Volume of the sphere = 682.6π cubic units. [approx] (Ans)

__________________________________

3. Radius (r) of the sphere = 5 units. (Given)

• Surface area of the sphere = 4πr².

Surface area of the sphere = 4 × π × (5)²

Surface area of the sphere = 4 × π × 5 × 5

Surface area of the sphere = 100π units. (Ans)

And,

• Volume of the sphere = 4/3πr³.

Volume of the sphere = 4/3 × π × (5)³

Volume of the sphere = 4/3 × π × 5 × 5 × 5

Volume of the sphere = 500π/3

Volume of the sphere = 166.6π cubic units. [approx] (Ans)

__________________________________

4. Diameter of the sphere = 18 units. (Given)

Radius (r) of the sphere = 18/2 = 9 units.

• Surface area of the sphere = 4πr².

Surface area of the sphere = 4 × π × (9)²

Surface area of the sphere = 4 × π × 9 × 9

Surface area of the sphere = 324π units. (Ans)

And,

• Volume of the sphere = 4/3πr³.

Volume of the sphere = 4/3 × π × (9)³

Volume of the sphere = 4/3 × π × 9 × 9 × 9

Volume of the sphere = 2916π/3

Volume of the sphere = 972π cubic units. (Ans)

__________________________________

5 0
3 years ago
Students who party before an exam are twice as likely to fail as those who don't party (and presumably study). If 20% of the stu
True [87]

Answer:

The fraction of the students who failed to went partying = \frac{1}{10}

Step-by-step explanation:

Let total number of students = 100

No. of students partied are twice the no. of students who not partied.

⇒ No. of students partied = 2 × the no. of students who are not partied

No. of students partied before the exam = 20 % of total students

⇒ No. of students partied before the exam = \frac{20}{100} × 100

⇒ No. of students partied before the exam =  20

No. of students who not partied before the exam = \frac{20}{2} = 10

Thus the fraction of the students who failed to went partying = \frac{10}{100} = \frac{1}{10}

8 0
4 years ago
Help please, giving BRAINLIEST!!!
PtichkaEL [24]
10 have a good day byeeee
4 0
3 years ago
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