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Lera25 [3.4K]
3 years ago
9

Figure RST is reflected about the x-axis and then translated down 1 unit to obtain figure R’S’T’:Which statement best describes

the relationship between the two figures?
Figure RST is congruent to figure R’S’T’.
Figure RST is bigger than figure R’S’T’.
The measure of angle R is equal to the measure of angle S’.
The measure of angle R is equal to the measure of angle T’.

Mathematics
1 answer:
stepan [7]3 years ago
6 0

h.........

....................,...,........

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Find the difference between and 8/15 - -(2/3). Show all calculations in your final answer please!! :)
sasho [114]

Answer:

\boxed{\dfrac{34}{15}}

Step-by-step explanation:

\text{Use }\LaTeX (ノ◕ヮ◕)ノ*:・゚✧

\dfrac{8}{5} - - \left(\dfrac{2}{3}\right)

\dfrac{8}{5} - \left[-\dfrac{2}{3}\right]

\dfrac{8}{5} +\dfrac{2}{3}

\dfrac{8(3)}{5(3)} +\dfrac{2(5)}{3(5)}

\dfrac{24}{15} +\dfrac{10}{15}

\boxed{\dfrac{34}{15}}

3 0
3 years ago
Read 2 more answers
How do you solve this? Thank you
V125BC [204]
2)

a)

\bf a^{\frac{{ n}}{{ m}}} \implies  \sqrt[{ m}]{a^{ n}} \qquad \qquad
\sqrt[{ m}]{a^{ n}}\implies a^{\frac{{ n}}{{ m}}}\\\\
-------------------------------\\\\
(4x^5\cdot x^{\frac{1}{3}})+(2x^4\cdot x^{\frac{1}{3}})-(7x^3\cdot x^{\frac{1}{3}})+(3x^2\cdot x^{\frac{1}{3}})\\\\+(9x^1\cdot x^{\frac{1}{3}})-(1\cdot x^{\frac{1}{3}})
\\\\\\
4x^{5+\frac{1}{3}}+2x^{4+\frac{1}{3}}-7x^{3+\frac{1}{3}}+9x^{1+\frac{1}{3}}-x^{\frac{1}{3}}

\bf 4x^{\frac{16}{3}}+2x^{\frac{13}{3}}-7x^{\frac{10}{3}}+9x^{\frac{4}{3}}-x^{\frac{1}{3}}
\\\\\\
4\sqrt[3]{x^{16}}+2\sqrt[3]{x^{13}}-7\sqrt[3]{x^{10}}+9\sqrt[3]{x^4}-\sqrt[3]{x}

b)

\bf \cfrac{4x^5+2x^4-7x^3+3x^2+9x-1}{x^{\frac{1}{3}}}\impliedby \textit{distributing the denominator}
\\\\\\
\cfrac{4x^5}{x^{\frac{1}{3}}}+\cfrac{2x^4}{x^{\frac{1}{3}}}-\cfrac{7x^3}{x^{\frac{1}{3}}}+\cfrac{3x^2}{x^{\frac{1}{3}}}+\cfrac{9x}{x^{\frac{1}{3}}}-\cfrac{1}{x^{\frac{1}{3}}}
\\\\\\
(4x^5\cdot x^{-\frac{1}{3}})+(2x^4\cdot x^{-\frac{1}{3}})-(7x^3\cdot x^{-\frac{1}{3}})+(3x^2\cdot x^{-\frac{1}{3}})\\\\+(9x^1\cdot x^{-\frac{1}{3}})-(1\cdot x^{-\frac{1}{3}})

\bf 4x^{5-\frac{1}{3}}+2x^{4-\frac{1}{3}}-7x^{3-\frac{1}{3}}+9x^{1-\frac{1}{3}}-x^{-\frac{1}{3}}
\\\\\\
4x^{\frac{14}{3}}+2x^{\frac{11}{3}}-7x^{\frac{8}{3}}+9x^{\frac{2}{3}}-x^{-\frac{1}{3}}
\\\\\\
4\sqrt[3]{x^{14}}+2\sqrt[3]{x^{11}}-7\sqrt[3]{x^{8}}+9\sqrt[3]{x^{2}}-\frac{1}{\sqrt[3]{x}}



3)

\bf \begin{cases}
f(x)=\sqrt{x}-5x\implies &f(x)x^{\frac{1}{2}}-5x\\\\
g(x)=5x^2-2x+\sqrt[5]{x}\implies &g(x)=5x^2-2x+x^{\frac{1}{5}}
\end{cases}
\\\\\\
\textit{let's multiply the terms from f(x) by each term in g(x)}
\\\\\\
x^{\frac{1}{2}}(5x^2-2x+x^{\frac{1}{5}})\implies x^{\frac{1}{2}}5x^2-x^{\frac{1}{2}}2x+x^{\frac{1}{2}}x^{\frac{1}{5}}

\bf 5x^{\frac{1}{2}+2}-2x^{\frac{1}{2}+1}+x^{\frac{1}{2}+\frac{1}{5}}\implies \boxed{5x^{\frac{5}{2}}-2x^{\frac{3}{2}}+x^{\frac{7}{10}}}
\\\\\\
-5x(5x^2-2x+x^{\frac{1}{5}})\implies -5x5x^2-5x2x+5xx^{\frac{1}{5}}
\\\\\\
-25x^3+10x^2-5x^{1+\frac{1}{5}}\implies \boxed{-25x^3+10x^2-5x^{\frac{6}{5}}}

\bf 5\sqrt{x^5}-2\sqrt{x^3}+\sqrt[10]{x^7}-25x^3+10x^2-5\sqrt[5]{x^6}
6 0
3 years ago
Juan and his little brother Miguel ran around a circular track together. Juan ran on the inner track, which has a radius of 30 f
eduard

Answer:

80pi-60pi

Step-by-step explanation:

To find how much Juan ran, we must find the circumference.

pi *30*2=60*pi  (which is how much Juan ran.)

pi*40*2=80*pi (which is how much Miguel ran)

80pi-60pi would be how much farther Miguel ran than Juan.

8 0
3 years ago
I need help with C, thank you.
guapka [62]
Simple....

\frac{3}{4} x\ \textless \  \frac{9}{2}

x<6

This means that on your graph at 6 it's a circle (not colored in) and it goes to the left indefinitely...

Thus, your answer.
6 0
3 years ago
Chords AB and CD intersect at point E, AE = 10, EB = 4, and CE = 8. Therefore, ED =
Genrish500 [490]
So here is how we are going to find out what is ED. 
Based on the given figure, it states that, AE is 10, and EB is 4 and CE is 8.
So, <span>(AE/CE)=(ED/EB)
10/8 = ED/4 <<multiply both sides by the common denominator which is 8 and the result would be:
80/8 = 8ED/4
10 = 2ED <<divide both sides by 2 and we get
ED = 5.
Therefore, the measurement of ED is 5. 
Hope this answer helps. Let me know if you need more help next time!</span>
5 0
3 years ago
Read 2 more answers
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