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Bad White [126]
3 years ago
8

Plz help. Thank you!

Mathematics
1 answer:
NARA [144]3 years ago
3 0
The new surface area will be 9 times the old surface area.

So A or #1
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A local gym instructor has a course load that allows her to teach eight classes. At an interest meeting, 8 people wanted high-­‐
cricket20 [7]

Answer:

<u>The final curse load of the local gym instructor is this:</u>

<u>High-­‐impact aerobics = 1</u>

<u>Low-­‐impact aerobics =  4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

Step-by-step explanation:

1. Let's apportion the class load using the Hamilton method

Number of classes the local gym instructor can teach = 8

Total number of students that want to take a class = 114 (8 people wanted high-­‐impact aerobics, 64 wanted low-­‐impact aerobics, 11 wanted jazzercise, and 31 wanted step exercise)

Standard divisor = 114/8 = 14.25

Now, we can apportion the students in in Standard quotas, this way:

High-­‐impact aerobics = 8/14.25 = 0.5614

Low-­‐impact aerobics = 64/14.25 = 4.49

Jazzercise = 11/14.25 = 0.7719

Step exercise = 31/14.25 = 2.1754

Now, we find the Minimum quota, just considering the whole number and don't taking into account the decimals, this way:

High-­‐impact aerobics = 0

Low-­‐impact aerobics =  4

Jazzercise = 0

Step exercise = 2

As we can see we have 6 classes and there are 2 still pending. Those 2 goes to the classes with the highest decimal portion, in this case, Jazzercise .7719 and High-­‐impact aerobics with .5614.

<u>The final course load is this:</u>

<u>High-­‐impact aerobics = 1</u>

<u>Low-­‐impact aerobics =  4</u>

<u>Jazzercise = 1</u>

<u>Step exercise = 2</u>

7 0
3 years ago
In​ Marissa's calculus​ course, attendance counts for 15​% of the​ grade, quizzes count for 20​% of the​ grade, exams count for
Alexandra [31]

Answer:

Her average was 87.35% on this course.

Step-by-step explanation:

In order to determine Marissa's average we need to take the average she has on each of the cattegories and find how much that relates to the weight of the  cattegory on the final grade. We have:

Attendance counts for 15% of the grade and she has 100% average on that. So we have:

attendance = weight*(Marissa's average)

attendance = 15%*(100/100) = 15%

Quizzes counts for 20% of the grade and she has a 93% average on that. So we have:

Quizzes = weigth*(Marissa's average)

Quizzes = 20%*(93/100) = 18.6 %

Exams counts for 50% of the grade and she has a 82% average on that. So we have:

Exams = weigth*(Marissa's average)

Exams = 50%*(82/100) = 41%

The final exam counts for 15% of the grade and she has a average of 85% on that so we have:

Finals = 15%*(85/100) = 12.75%

So her grade is the sum of all the cattegories:

Course's average = 15+18.6+41+12.75 = 87.35 %

4 0
3 years ago
Read 2 more answers
5,000 is invested at an interest rate of 8% compounded annually. how much is the investment return after 20 years?​
iren [92.7K]

Step-by-step explanation:

5k×8×20

_______ =800

100

6 0
2 years ago
Read 2 more answers
Here are two sets of numbers, a and b. Set a :200,104,100,160. Set b: 270,400,483,300, x. Mean of set a: mean of set b= 3:8. Wor
LenKa [72]

Given:

The given sets are:

Set a : 200, 104, 100, 160.

Set b: 270, 400, 483, 300, x.

Mean of set a: mean of set b= 3:8

To find:

The value of x.

Solution:

Formula for mean:

Mean=\dfrac{\text{Sum of observations}}{\text{Number of observation}}

The mean of set of a is:

Mean=\dfrac{200+104+100+160}{4}

Mean=\dfrac{564}{4}

Mean=141

The mean of set of b is:

Mean=\dfrac{270+400+483+300+x}{5}

Mean=\dfrac{1453+x}{5}

Mean=\dfrac{1453+x}{5}

It is given that,

Mean of set a: mean of set b= 3:8

\dfrac{141}{\dfrac{1453+x}{5}}=\dfrac{3}{8}

\dfrac{705}{1453+x}=\dfrac{3}{8}

8\times 705=3\times (1453+x)

5640=4359&#10;+3x

Isolate the variable x.

5640-4359&#10;=3x

1281&#10;=3x

Divide both sides by 3.

\dfrac{1281}{3}&#10;=x

427&#10;=x

Therefore, the value of x is 427.

3 0
2 years ago
The demand for video recorders has been estimated to be Qv = 134 − 1.07Pf + 46Pm − 2.1Pv − 5I, where Qv is the quantity of video
stepladder [879]

Answer:

The Video recorders are inferior goods.

Step-by-step explanation:

As Q_{v} =134-1.07Pf+46Pm-2.1Pv-5I

where;

The price of the recorders films are increasing by a term 1.07 which gives that the Price is increasing by a little. Also adding the Price of video recorder is increasing by a factor 2.1 and the Revenue or income is increasing by a term 5 (Which is high) so, revenue and price are increasing leaving the quality of the voice recorder decreasing by a large margin for maintaining the balance.

As

                               Revenue =price*Quality

So, in conclusion the quality decreases and thus the video recorders are inferior goods.

5 0
3 years ago
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