The equation of the line that passes through the point (-6,-3) and has a slope of 0 is y = -3
The line is passing through the point = (-6,-3)
The slope of the line = 0
The point slope form is

Substitute the values in the equation
(y-(-3)) = 0×(x-(-6))
We have to convert this equation the slope intercept form
Slope intercept form is
y = mx + b
Where m is the slope of the line
b is the y intercept
(y-(-3)) = 0×(x-(-6))
y+3 = 0×(x+6)
y+3 = 0
y = -3
Hence, the equation of the line that passes through the point (-6,-3) and has a slope of 0 is y = -3.
Learn more about slope intercept form here
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9514 1404 393
Answer:
140°
Step-by-step explanation:
Angles 1 and 3 are "corresponding" angles, so are congruent.
∠1 = ∠3
20x +60 = 30x +20
40 = 10x . . . . . . . . . . . . subtract 20x+20
4 = x . . . . . . . . . . . . . . divide by 10
∠1 = 20x +60 = 20(4) +60 = 80 +60
∠1 = 140°
Let , coordinate of points are P( h,k ).
Also , k = 3h + 1
Distance of P from origin :

Distance of P from ( -3, 4 ) :

Now , these distance are equal :

Solving above equation , we get :

Hence , this is the required solution.
Answer:
5
Step-by-step explanation: