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4 years ago

What is the net charge if there are 3 protons and 3 electrons

Chemistry

1 answer:

Thepotemich [5.8K]4 years ago

8 0

Answer:

sorry i think that was science

Explanation:

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This is when an organism like insects or plants become trapped in amber

BigorU [14]

thats very nice lol, things stuck in amber are very cool

5 0

3 years ago

Explain how changing the concentration of reactants can affect the rate of reaction.

Stells [14]

Answer:

Increasing the concentration of a substance will increase the rate of reaction because in a conc substance the particles are more clustered together and this causes more effective collisions thus increasing the rate of reaction and when the substance isn't concentrated the particles aren't really close and this reduces the rate of reaction because alot of collisions can't be made compared to that of the concentrated substance

3 0

4 years ago

How many water molecules are produced when 5.2g O2 are reacted

gtnhenbr [62]

Answer:

Total number of water molecules produced after the reaction is 1.956×10^22 molecules of water.

Explanation:

By the reaction

H2+ 1/2 O2 → H2O

Moles of O2 = 5.2\32

⇒1 mole of O2 produce 1 mole of H2O

1 mole O2 will produce 2 mole of H2O

Therefore, 5.2\32 mole will produce ${2}\times{\frac{5.2}\times{32}}$

⇒ Molecules of H2O will be

${2}\times{\frac{5.2}{32}}$ = $\frac{x}{{6.02}\times{10^23}}$

= 1.956×10^22 moleculesof H2O.

5 0

3 years ago

4. Pb +FeSO, - PbSO, +Fe Reaction Type:

Studentka2010 [4]

Answer:Fe

Explanation:

8 0

3 years ago

Based on the recipe for the Dextrose Calcium Carbonate (DCC) medium, what is the percent concentration (%weight/volume) of dextr

yanalaym [24]

Answer: The percent concentration ( % m/v) of dextrose in the solution is 2 %

Explanation:

We are given:

Mass of Yeast Extract = 5.0 grams

Mass of $K_2HPO_4$ = 1.0 grams

Mass of $MgSO_4$ = 0.5 grams

Mass of Dextrose = 20.0 grams

Mass of $CaCO_3$ = 10. grams

Mass of Agar = 18.0 grams

Volume of solution = 1 L = 1000 mL (Conversion factor: 1 L = 1000 mL)

% (m/v) is defined as the concentration, which is mass of solute present in 100 mL of solution

To calculate the mass of solute, we apply unitary method:

In 1000 mL of solution, the mass of dextrose present is 20.0 grams

So, in 100 mL of solution, the mass of dextrose present will be = $\frac{20.0}{1000}\times 100=2g$

Calculating the % (m/v) of dextrose, we get:

$\% \text{(m/v) of dextrose}=\frac{\text{Mass of dextrose}}{\text{Volume of solution}}\times 100\\\\\% \text{(m/v) of dextrose}=\frac{2g}{100mL}\times 100=2\%$

Hence, the percent concentration ( % m/v) of dextrose in the solution is 2 %

4 0

4 years ago