Explanation:
protons have a relative charge of +1, they are located in the nucleus and the carry a positive charge
the electrons are negatively charged and have a charge of -1 . They are found orbiting on the shells .the electrons have a negligible mass of 1 / 1840
the neutrons have no charge they are located in the nucleus of an atom .
Answer:
115.2 °C since melting point is an intensive property
Step-by-step explanation:
The melting point of a substance does not depend on how much you have.
For example, the melting point of water is 0 °C, whether it is an ice cube from the refrigerator or in the frozen pond outside.
The freezing point of a substance is an <em>intensive property</em>.
Thus, the melting point of 100 g of sulfur is 115.2 °C because melting point in an intensive property.
Answer:
The 
solution has a higher osmotic pressure and higher boiling point than LiCl solution.
Explanation:
As concentrations of two aqueous solutions are same therefore we can write:
, 
and 
where 
, 
and 
are lowering of vapor pressure, elevation in boiling point and osmotic pressure of solution respectively. 
is van't hoff factor.
= total number of ions generated from dissolution of one molecule of a substance (for strong electrolyte).
Here both and LiCl are strong electrolytes.
So, 
and 
Hence, lowering of vapor pressure, elevation in boiling point and osmotic pressure will be higher for solution.
Therefore the solution has a higher osmotic pressure and higher boiling point than LiCl solution.
Enzymes affect the rate of the reaction in both the forward and reverse directions; the reaction proceeds faster because less energy is required for molecules to react when they collide. Thus, the rate constant (k) increases. Figure 3: Lowering the Activation Energy of a Reaction by a Catalyst.
<em>Best of luck,</em>
<em>-Squeak</em>
Answer:
Hydrogen ion concentration is 2.773E-4Mole per DM3
Hydroxide ion concentration is 4.093E-11
It is an acid
Explanation:
PH(H3O)=-LogH3O
PH=3.557
H3O=antilog of -3.557
antilog of -3.557=antilog (0.443 -4)
antilog0.443 ×antilog -4=2.773E-4mole per DM3.
(H3O)(OH)=10^-14
H30=2.773×10^-14
OH= 1.00E-14/2.773E-4
=4.093E-11
it is an acid since the concentration of hydrogen ion is more than the hydroxide ion
