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3 years ago

How to find the number of neutrons in an isotope?

1 answer:

4 0

Chemical properties of elements are primarily determined by the electrons but not by neutrons. Therefore, the isotopes of the same element have similar chemical behavior. (a) The atomic number is 17, so there are 17 protons and 17 electrons. The mass number is 35, so there are 18 (=35-17) neutrons. Hope this helps. :)

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If I initially have a gas at a pressure of 10.0 atm, a volume of 24.0 liters, and a temperature

Bezzdna [24]

Answer:

The new volume of gas is 25.7 L.

Explanation:

Given data:

Initial volume = 24.0 L

Initial pressure = 10.0 atm

Initial temperature = 200 K

Final temperature = 300 K

Final volume = ?

Final pressure = 14.0 atm

Formula:

P₁V₁/T₁ = P₂V₂/T₂

P₁ = Initial pressure

V₁ = Initial volume

T₁ = Initial temperature

P₂ = Final pressure

V₂ = Final volume

T₂ = Final temperature

Solution:

V₂ = P₁V₁ T₂/ T₁ P₂

V₂ = 10.0 atm × 24.0 L × 300K / 200 K × 14.0 atm

V₂ = 72000 atm .L. K / 2800 K.atm

V₂ = 25.7 L

The new volume of gas is 25.7 L.

5 0

4 years ago

Synthesize Information In a multistep process, cells can combine the reactants glucose (C6H12O6) and oxygen (O2) to form the pro

zloy xaker [14]

Answer:

Explanation:

In one of the process, energy is built up from scratch, in the other one, energy is liberated for use by an organism or body.

The first process deals with a metabolic reaction in which energy is liberated:

C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O + energy

In the above process, energy is liberated when glucose combines with oxygen. The waste products are carbon dioxide and water. This process liberates heat energy which can be used to do work.

In the reverse process:

6CO₂ + 6H₂O → C₆H₁₂O₆ + 6O₂

This process stores energy in carbon chains as chemical energy. It is this energy that is released in the first process.

Therefore, we can see that the first process liberates energy and the reverse process stores energy.

8 0

3 years ago

write equations to show the chemical processes which occur when the first ionization and the second ionization energies of lithi

diamong [38]

Answer:

First ionization of lithium:

$\text{Li}\;(g)\to \text{Li}^{+} \; (g) + \text{e}^{-}$ .

Second ionization of lithium:

$\text{Li}^{+}\;(g) \to\text{Li}^{2+} \;(g) + \text{e}^{-}$ .

Explanation:

The ionization energy of an element is the energy required to remove the outermost electron from an atom or ion of the element in gaseous state. (Refer to your textbook for a more precise definition.) Some features of the equation:

Start with a gaseous atom (for the first ionization energy only) or a gaseous ion. Write the gaseous state symbol $(g)$ next to any atom or ion in the equation.
The product shall contain one gaseous ion and one electron. The charge on the ion shall be the same as the order of the ionization energy. For the second ionization energy, the ion shall carry a charge of +2.
Charge shall balance on the two sides of the equation.

First Ionization Energy of Li:

The products shall contain a gaseous ion with charge +1 $\text{Li}^{+}\;(g)$ as well as an electron $\text{e}^{-}$ .
Charge shall balance on the two sides. There's no net charge on the product side. Neither shall there be a charge on the reactant side. The only reactant shall be a lithium atom which is both gaseous and neutral: $\text{Li}\;(g)$ .

Hence the equation: $\text{Li}\;(g) \to \text{Li}^{+}\;(g) + \text{e}^{-}$ .

Second Ionization Energy of Li:

The product shall contain a gaseous ion with charge +2: $\text{Li}^{2+}\;(g)$ as well as an electron $\text{e}^{-}$ .
Charge shall balance on the two sides. What's the net charge on the product side? That shall also be the charge on the reactant side. What will be the reactant?