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3 years ago

Calculate the number of atoms

Chemistry

1 answer:

erastova [34]3 years ago

4 0

Explanation:

13 are the number of atoms

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Consider the reaction below. At 500 K, the reaction is at equilibrium with the following concentrations. [PCI5]= 0.0095 M [PCI3]

Dmitriy789 [7]

Answer: The equilibrium constant for the given reaction is 0.0421.

Explanation:

$PCl_5\rightleftharpoons PCl_3+Cl_2$

Concentration of $[PCl_5]$ = 0.0095 M

Concentration of $[PCl_3]$ = 0.020 M

Concentration of $[Cl_2]$ = 0.020 M

The expression of the equilibrium constant is given as:

$K_c=\frac{[PCl_3][Cl_2]}{[PCl_5]}=\frac{0.020 M\times 0.020 M}{0.0095 M}$

$K_c=0.0421$ (An equilibrium constant is an unit less constant)

The equilibrium constant for the given reaction is 0.0421.

6 0

3 years ago

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Which element would make a poor, brittle conductor? use the periodic table for help. a. sulfur b. boron c. cobalt d. calcium?

Greeley [361]

I think the answer is C or B

8 0

3 years ago

Covalent bonding is the ____ of electrons

taurus [48]

Answer: sharing

Reason: They do this to gain stability. The reason they don’t actually transfer is because the difference in electronegativity values are above a certain value.

8 0

3 years ago

Gifblaar is a small South African shrub and one of the most poisonous plants known because it contains fluoroacetic acid (FCH2CO

PSYCHO15rus [73]

[H_{3}O^{+}] = 0.00770 M

The equilibrium equation representing the dissociation of $FCH_{2}COOH$

$FCH_{2}COOH(aq) + H_{2}O (l) FCH_{2}COO^{-}(aq)+ H_{3}O^{+}(aq)$

Given [H_{3}O^{+}] = 0.00770 M

Let the initial concentration of acid be x and change y

So y = $[H_{3}O^{+}]$ = $[FCH_{2}COO^{-}]$ = 0.00770 M

$pK_{a} = 2.59K_{a} = 10^{-2.59} = 0.00257 M$

$K_{a} = \frac{(0.00770 M)(0.00770 M)}{x - 0.00770}$

$0.00257 = \frac{0.00005929}{x - 0.00770}$

0.00257 x - 0.00001979 = 0.00005929

x = 0.031 M

Therefore, initial concentration of the weak acid is 0.031 M

4 0

3 years ago

What is the mass of 1 mole of lithium?

Korolek [52]

Answer: The mass of 1 mole of lithium is 6.941 grams.

Explanation:

To calculate the mass of a compound or element, we use the formula used to calculate the number of moles:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$

Where,

Number of moles of lithium = 1 mole

Given mass of lithium = ? g

Molar mass of lithium = 6.941 g/mol

Putting value in above equation, we get:

$1mole=\frac{\text{Given mass}}{6.941g/mol}\\\\\text{Mass of lithium}=6.941g$

Hence, the mass of 1 mole of lithium is 6.941 grams.

5 0

2 years ago

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