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3 years ago

7

How do you do this

1 answer:

chubhunter [2.5K]3 years ago

7 0

Answer:

a 9 b 1 c 1 d g(x)=1×3^x

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If one endpoint of a line segment is (2, 8) and the midpoint is (-4, 7), what is the other endpoint? (8, -5)

Pepsi [2]

( - 10, - 22 )

using the midpoint formula,

let the other endpoint have coordinates (x, y) then

$\frac{1}{2}$ (2 + x ) = - 4 ( multiply through by 2 )

2 + x = - 8 ( subtract 2 from both sides ) then

x = -8 - 2 = - 10 ← value of x-coordinate

Similarly for y-coordinate

$\frac{1}{2}$ (8 + y ) = - 7 ( multiply through by 2 )

8 + y = - 14 ( subtract 8 from both sides )

y = - 14 - 8 = - 22 ← y -coordinate

the other endpoint is ( - 10, - 22 )

7 0

3 years ago

Help ixl sucks pleasssssssssssse

LUCKY_DIMON [66]

Answer:

11.5

Step-by-step explanation:

98.9 / 8.6 = 11.5

6 0

3 years ago

Read 2 more answers

Drag the tiles to the correct boxes to complete the pairs.Not all tiles will be used match the equations representing parabolas

IceJOKER [234]

Answer:

$y=-8.08$ -------> $y+8=3(x+2)^{2}$

$y=14.25$ -------> $y-14=-(x-3)^{2}$

$y=-7.625$ -----> $y+7.5=2(x+2.5)^{2}$

$y=17.25$ -------> $y-17=-(x-3)^{2}$

$y=-7.25$ -------> $y+7=(x-4)^{2}$

$y=6.25$ -------> $y-6=-(x-1)^{2}$

Step-by-step explanation:

we know that

The standard form of a vertical parabola is equal to

$(x-h)^{2}=4p(y- k)$

where

(h,k) is the vertex

the focus is (h, k + p)

and

the directrix is y = k - p

Part 1) we have

$y+8=3(x+2)^{2}$

Convert to standard form

$(x+2)^{2}=(1/3)(y+8)$

The vertex is the point $(-2,-8)$

$h=-2,k=-8$

$4p=1/3$

$p=1/12$

the directrix is equal to

$y = k-p$ -----> $y=-8-(1/12)=-8.08$

Part 2) we have

$y-14=-(x-3)^{2}$

Convert to standard form

$(x-3)^{2}=-(y-14)$

The vertex is the point $(3,14)$

$h=3,k=14$

$4p=-1$

$p=-1/4$

the directrix is equal to

$y = k-p$ -----> $y = 14-(-1/4)=14.25$

Part 3) we have

$y+7.5=2(x+2.5)^{2}$

Convert to standard form

$(x+2.5)^{2}=(1/2)(y+7.5)$

The vertex is the point $(-2.5,-7.5)$

$h=-2.5,k=-7.5$

$4p=1/2$

$p=1/8$

the directrix is equal to

$y = k-p$ -----> $y=-7.5-(1/8)=-7.625$

Part 4) we have

$y-17=-(x-3)^{2}$

Convert to standard form

$(x-3)^{2}=-(y-17)$

The vertex is the point $(3,17)$

$h=3,k=17$

$4p=-1$

$p=-1/4$

the directrix is equal to

$y = k-p$ -----> $y = 17-(-1/4)=17.25$

Part 5) we have

$y+7=(x-4)^{2}$

Convert to standard form

$(x-4)^{2}=(y+7)$

The vertex is the point $(4,-7)$

$h=4,k=-7$

$4p=1$

$p=1/4$

the directrix is equal to

$y = k-p$ -----> $y=-7-(1/4)=-7.25$

Part 6) we have

$y-6=-(x-1)^{2}$

Convert to standard form

$(x-1)^{2}=-(y-6)$

The vertex is the point $(1,6)$

$h=1,k=6$

$4p=-1$

$p=-1/4$

the directrix is equal to

$y = k-p$ -----> $y=6-(-1/4)=6.25$

4 0

3 years ago

a car deceased in value by 25% in the first year. purchased for $28,000, what is the car worth today.

Gwar [14]

Try this: Principal times (1+interest rate as a decimal fraction)^(number of yrs)

In this case, Principal = $28,000; interest rate = -0.25; # of years = 1

So Decrease in value = $28,000 (0.75)^1 = $21,000.

4 0

3 years ago

Help, please!! I need the answer

Lorico [155]

Answer:

D

Step-by-step explanation:

5 0

3 years ago