First one is D and second one is C
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Answer: 12r + 3
Step-by-step explanation:
6r+3(2r+1)
Apply BODMAS, do bracket first
6r + (6r + 3)
Do addition next
= 12r + 3
Question is a bit vague. If you wish to graph this inequality, you'll need to know what the graph of the absolute value function y = |x| looks like; it's a " V " with the vertex at the origin. The slope of the right half of the graph is m=1. Draw this function.
Next, subtract 2 from both sides. We'll get <span> |x + 1| < –1 - 2
or
</span> |x + 1| < –3. We can stop here! Why! because the absolute value function is never smaller than zero, and so <span> |x + 1| is never smaller than -3.
You could, of course, graph y = |x+1|; start with your graph for y = |x| and then move the whole graph 1 unit to the left (away from the origin). If you do this properly you'll see that the entire graph is above the x-axis, except for the vertex (-1,0). Again, that tells us that the given inequality has no solution.
</span>
Answer: Red
Step-by-step explanation:
The y intercept is -2 so its either green or red
the slope is positive so its red
