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olasank [31]
3 years ago
8

What is the speed of light in carbon disulphide if its refractive index is 1.628?

Physics
1 answer:
Marina CMI [18]3 years ago
6 0
Refractive index (symbol n) is defined as the ratio of the velocity of light in a vacuum (symbol c) to the velocity of light in a medium (symbol v). The equation is n=c/v. In order to obtain the speed of light in carbon disulphide the above equation needs to be rearranged to make v the subject. This yields v=c/n. Plugging the numbers in yields a speed to 1.84x10^8 metres per second. 
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If a team of workers comes to a consensus, what probably happened in the meeting?
Feliz [49]

Answer:

A

Explanation:

A consensus is when you come to an agreement

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Which statement is true of a glass lens that diverges light in air?
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C it is uniformly thick
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If the elevation in reservoir b is 100m, what must the elevation in reservoir a be if thevolume flow rate through the cast-iron
Zinaida [17]

The elevation in reservoir  at  the rate of flow using is 03m/s  is 114m.

The Reynolds range is the ratio of inertial forces to viscous forces. The Reynolds variety is a dimensionless variety used to categorize the fluids structures in which the impact of viscosity is crucial in controlling the velocities or the flow sample of a fluid.

The reason of the Reynolds number is to get a few experience of the relationship in fluid glide between inertial forces (this is those that maintain going by using Newton's first law – an item in motion stays in movement) and viscous forces, this is people who cause the fluid to come back to a forestall because of the viscosity of the fluid.

calculation,

Let L = 100 m pipe

     L1 = 150 m pipe

H f = friction losses

Using Reynolds number, relative  roughness, friction co- effiicients and friction losses

Substitute the value in equation

Z = 110= 0.48= 3.54

Z = 114m

Therefore water surface elevation at reservoir  is 114 meter.

Learn more about rate of flow here:-brainly.com/question/21630019

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6 0
2 years ago
The initial kinetic energy imparted to a 0.25 kg bullet is 1066 J. The acceleration of gravity is 9.81 m/s 2 . Neglecting air re
lubasha [3.4K]

Answer:

The range of the bullet is 0.435 kilometers.

Explanation:

According to the problem, maximum height is equal to the range of the bullet. That is:

\Delta x = \Delta y

Where:

\Delta x - Range of the bullet, measured in meters.

\Delta y - Maximum height of the bullet, measured in meters.

By the Principle of Energy Conservation, gravitational potential energy reaches its maximum at the expense of the initial kinetic energy. That is to say:

K_{1} = U_{2}

Where:

K_{1} - Kinetic energy at point 1, measured in joules.

U_{1} - Gravitational potential energy at point 2, measured in joules, and:

U_{2} = m\cdot g \cdot \Delta y

Where:

m - Mass of the bullet, measured in kilograms.

g - Gravitational constant, measured in meters per square second.

The maximum height is now cleared:

K_{1} = m\cdot g \cdot \Delta y

\Delta y = \frac{K_{1}}{m\cdot g}

If K_{1} = 1066\,J, m = 0.25\,kg and g = 9.81\,\frac{m}{s^{2}}, the maximum height is now computed:

\Delta y = \frac{1066\,J}{(0.25\,kg)\cdot \left(9.807\,\frac{m}{s^{2}} \right)}

\Delta y = 434.791\,m

\Delta y = 0.435\,km

Lastly, the range of the bullet is 0.435 kilometers.

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3 years ago
Calculate the speed of magnetic field rotation in an ac machine with 4 poles operating at the frequency of 60 hz.
geniusboy [140]
I think the answer is 15hz
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