Answer:
a vacuum formed above the column of mercury in a mercury barometer.
Answer:
( About ) 6.8nC
Explanation:
We are given the equation |Q2| = mgd^2 / kQ1. Let us substitute known values into this equation, but first list the given,
Charge Q2 = +45nC = (45 × 10⁻⁹) C
mass of charge Q2 = 4.5 μg, force of gravity = 4.5 μg × 9.8 m/s² = ( 4.41 × 10^-5 ) N,
Distance between charges = 25 cm = 0.25 m,
k = Coulomb's constant = 9 × 10^9
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And of course, we have to solve for the magnitude of Q2, represented by the charge magnitude of the charge on Q2 -
(4.41 × 10^-5) = [(9.0 × 10⁹) × (45 × 10⁻⁹) × Q₂] / 0.25²
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Solution = ( About ) 6.8nC
Answer:
Personally I would pull over and wait the rain out in my car, preferably parked under a tree.
This is true - by having special features, newspapers and news stations can get a very specific and very targeted audience to listen to them or red their newspaper because they know that certain target audience will buy it just for the special feature. This can backfire, however.