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3 years ago

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A train traveling at a constant speed takes a passenger from Elm to Millwood, stopping at Centre along the way. It takes times a

s long to go from Centre to Millwood as it does to go from Elm to Centre. The entire trip is miles. How far is the ride from Centre to Millwood? Name a geometric postulate or theorem used to find the solution.
A. miles; segment addition postulate
B. miles; segment bisector theorem
C. miles; segment addition postulate
D. miles; segment bisector theorem

1 answer:

Zigmanuir [339]3 years ago

3 0

What are the numbers? I cant see the answers, but it would be one of the segment addition postulate ones

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Ayuda con mates por favor

QveST [7]

Answer:

a) $x = -1$ and $y = 5$ , b) $x = 2$ and $y = -1$ , c) $x = -2$ and $y = 1$ , d) $x = 2$ and $y = -9$ , e) $x = 2$ and $y = -2$ , f) $x = 2$ and $y = -1$ , g) $x = 2$ and $y = -1$ , h) $x = 1$ and $y = 2$ .

Step-by-step explanation:

Each system is solved as follows (Cada sistema es resuelto como sigue):

a) $2\cdot x + y = 3$ and $3\cdot x - y = -8$

$y = 3 - 2\cdot x$

$3\cdot x - 3 + 2\cdot x = -8$

$5\cdot x = -5$

$x = -1$

$y = 5$

b) $x - 2\cdot y = 4$ and $-x+3\cdot y = -5$

$x = 4 + 2\cdot y$

$-4-2\cdot y+3\cdot y = - 5$

$-4+y = -5$

$y = -1$

$x = 2$

c) $-2\cdot x + 5\cdot y = 9$ and $x - y = -3$

$x = y-3$

$-2\cdot y +6 +5\cdot y = 9$

$3\cdot y = 3$

$y = 1$

$x = -2$

d) $5\cdot x - 4\cdot y = 2$ and $3\cdot x + 2\cdot y = -12$

$3\cdot x + 2\cdot y = -12$

$6\cdot x + 4\cdot y = -24$

$4\cdot y = -6\cdot x -24$

$5\cdot x +6\cdot x +24 = 2$

$11\cdot x = -22$

$x = 2$

$y = -9$

e) $x + y = 0$ and $2\cdot x +3\cdot y = -2$

$y = -x$

$2\cdot x -3\cdot x = -2$

$-x = -2$

$x = 2$

$y = -2$

f) $3\cdot x + 5\cdot y = 1$ and $x + y = 1$

$y = 1 - x$

$3\cdot x + 5 - 5\cdot x = 1$

$-2\cdot x = -4$

$x = 2$

$y = -1$

g) $5\cdot x - 2\cdot y = 12$ and $4\cdot x + 3\cdot y = 5$

$x = \frac{12+2\cdot y}{5}$

$x = \frac{5-3\cdot y}{4}$

$\frac{12+2\cdot y}{5} = \frac{5-3\cdot y}{4}$

$4\cdot (12+2\cdot y) = 5\cdot (5-3\cdot y)$

$48 + 8\cdot y = 25 - 15\cdot y$

$23\cdot y = -23$

$y = -1$

$x = 2$

h) $7\cdot x + 8\cdot y = 23$ and $3\cdot x + 2\cdot y = 7$

$3\cdot x + 2\cdot y = 7$

$12\cdot x + 8\cdot y = 28$

$8\cdot y = 28 - 12\cdot x$

$7\cdot x +28-12\cdot x = 23$

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3 years ago

Find the perimeter of 3ft

myrzilka [38]

Answer:It would be 8ft ??

Step-by-step explanation: 3ft = 8ft

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3 years ago

An airplane travels 2416 kilometers against the wind in 4 hours and 2896 kilometers with the wind in the same amount of time. Wh

oee [108]

Answer: the rate of the plane in still air is 664 km/h and the rate of the wind is 60 km/h

Step-by-step explanation:

Let x represent the rate of the plane in calm air.

Let y represent the rate of the wind.

An airplane travels 2416 kilometers against the wind in 4 hours. This means that the total speed with which the plane flew is (x - y) mph.

Distance = speed × time

Distance travelled by the plane while flying against the wind is

2416 = 4(x - y)

Dividing both sides of the equation by 4, it becomes

604 = x + y- - - - - - - - - - - 1

It flew 2896 kilometers with the wind in the same amount of time.. This means that the total speed with which the plane flew with the wind is (x + y) mph.

Distance travelled by the plane while flying with the wind is

2896 = 4(x + y)

Dividing both sides of the equation by 2, it becomes

724 = x + y- - - - - - - - - - - 2

Adding equation 1 to equation 2, it becomes

1328 = 2x

x = 1328/2

x = 664

Substituting x = 664 into equation 2, it becomes

724 = 664 + y

y = 724 - 664

y = 60

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3 years ago

Find the value of the variable.

Vedmedyk [2.9K]

Answer:

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Step-by-step explanation:

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3 years ago

How you would convert the repeating, nonterminating decimal to a fraction? Explain the process as you solve the problem.

bixtya [17]

Answer:

x = 0.1515...

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100 x - x = 15.1515... - 0.1515...

99 x = 15

x = 15 / 99 = 3 ∙ 5 / 3 ∙ 33 = 5 / 33

0.1515... = 5 / 33

Step-by-step explanation:

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2 years ago