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Varvara68 [4.7K]
3 years ago
12

Factor the following expression 10x^5+5x^3-14x^2-7

Mathematics
1 answer:
padilas [110]3 years ago
5 0

Answer:

\left(2x^2+1\right)\left(5x^3-7\right)

Step-by-step explanation:

10x^5+5x^3-14x^2-7

\left(10x^5+5x^3\right)+\left(-14x^2-7\right)

-7\left(2x^2+1\right)+5x^3\left(2x^2+1\right)

=\left(2x^2+1\right)\left(5x^3-7\right)

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Sliva [168]

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x = 0

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Type the correct answer in each box. Spell all words correctly, and use numerals instead of words for numbers. If necessary, use
notka56 [123]

Answer:

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Step-by-step explanation:

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Answer:

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. Find a pair of integers whose product is  C

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3 years ago
Factorise 3(3x-y)-(y-3x)
snow_lady [41]

Answer:

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Given:

\displaystyle \large{3(3x-y)-(y-3x)}

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\displaystyle \large{3(3x-y)-(-3x+y)}\\\displaystyle \large{3(3x-y)+(3x-y)}

Notice that in the expression, we have both same (3x-y). Therefore, (3x-y) is our factor.

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Change u back to 3x-y:

\displaystyle \large{4(3x-y)}

Therefore, the factored expression is 4(3x-y).

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2 years ago
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