Answer:
4 (4m+5n)
Step-by-step explanation:
hope this helps
The weights are within 2 standard deviations of the mean are 8.9 lbs, 9.5 lbs and 10.4 lbs
<h3>How to determine the weights?</h3>
The given parameters are:
- Mean, μ = 9.5
- Standard deviation, σ = 0.5
The weights within 2 standard deviation is represented as:
μ - 2σ ≤ x ≤ μ + 2σ
Substitute known values
9.5 - 2(0.5) ≤ x ≤ 9.5 + 2(0.5)
Evaluate the product
9.5 - 1 ≤ x ≤ 9.5 + 1
Evaluate the sum
8.5 ≤ x ≤ 10.5
This means that the weights are between 8.5 and 10.5 (inclusive)
Hence, the weights are within 2 standard deviations of the mean are 8.9 lbs, 9.5 lbs and 10.4 lbs
Read more about standard deviation at:
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