What mass of calcium hydroxide is formed when 10.0g of calcium oxide reacts with 10.0g of water?

1 answer:

7 0

The mass of calcium hydroxide that is formed when 10.0 g of CaO reacts with 10.0 g of water is 13.024 grams

calculation

from the equation

CaO + H2O → Ca(OH)2,

1 moles of CaO reacted with 1 moles of H2O to form 1 moles of Ca(OH)2

find the moles of each reactant

moles=mass/molar mass

moles of CaO= 10 g/56 g/mol=0.179 moles

moles of H2O = 10 g/18 g/mol 0.556 moles

CaO is the limiting reagent therefore by use of mole ratio of CaO:Ca(OH)2 which is 1:1 moles of Ca(OH)2 is = 0.179 moles

mass= moles x molar mass

= 0.176 moles x 74 g/mol = 13.024 grams

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Answer:

The symbol of isotopes used for blood flow analysis is $\begin{array}{c}{141} \\ {58}\end{array} C e.$

<u>Explanation: </u>

Isotopes are the substances that exhibit the same atomic number but has a different mass number of an element.
The atomic number explains the number of protons present in the element and mass number explains the number of neutrons available in the element.
For blood flow analysis, the isotope element is cerium-141 and it is used in the chemical examination of blood flow particles.
Symbol used for this isotope is $\begin{array}{c}{141} \\ {58}\end{array} C e$ , where 141 indicates the amount of mass present and 58 indicates the proton number and 83 indicates neutron number present in that element.
The amount of mass in an atom is calculated by the sum of protons and neutrons present in it. Thus mass of isotope is 141 obtained by the sum of 58 protons and 83 neutrons present in that isotope.