Answer:
Atomic radius increases by increasing the atomic number.
Explanation:
Atomic radius
:
Atomic radius is the distance between nucleus of an atom to its outer most electronic shell.
Trend along group:
As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.
As the size of atom increases the ionization energy from top to bottom also decreases because it becomes easier to remove the electron because of less nuclear attraction and as more electrons are added the outer electrons becomes more shielded and away from nucleus.
The given data show that the atomic number in increased from 4 to 88 it means atomic radius also increased from 1.53Å to 2.83Å. It means the given data is the elements of periodic table present in group. It is the data of 2nd group of periodic table.
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it makes aloh
AlCl3 + 3NaOH = AlOH3 + 3NaCl
Al3+ + 3Cl- + 3Na+ + 3OH- = AlOH3 + 3Na+ + 3Cl-
all cancels out except
Al3+ + 3OH- = AlOH3
Cl is stable as a diatomic molecule where the 2 Cl atoms are held together by a covalent bond
molar mass of the diatomic molecule is 70.9 g/mol
therefore 70.9 g of Cl₂ is - 1 mol
then 140 g of Cl₂ is - 1/70.9 x 140 = 1.97 mol
there are 1.97 mol of Cl₂ present
Answer:
Pressure of neon = 1.17 atm
Pressure of hydrogen = 0.63 atm
Explanation:
Given data:
Number of moles of H₂ = 2.5 mol
Number of moles of Ne = 4.6 mol
Total pressure = 1400 mmHg (1400/760 = 1.8 atm)
Solution:
We will solve this problem through mole fraction method.
Total number of moles = 2.5 + 4.6 = 7.1
Mole fraction of H₂ Mole fraction of Ne
2.5 mol/7.1 mol= 0.35 4.6mol/7.1mol = 0.65
Pressure of hydrogen = 0.35 × 1.8 atm
Pressure of hydrogen = 0.63 atm
Pressure of neon = 0.65 × 1.8 atm
Pressure of neon = 1.17 atm
Total pressure which is already given is sum of partial pressure of hydrogen and neon gas.
0.63 atm + 1.17 atm = 1.8 atm