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alexandr402 [8]
3 years ago
10

Write numerals for each of the italicized number word names found in these examples. Earth’s moon is (a) two million, one hundre

d fifty-five thousand, one hundred twenty miles across. The closest distance between Earth and the moon is (b) two hundred twenty-five million, sixty thousand miles. The farthest distance between them is (c) two hundred fifty-one million, seven hundred twenty thousand miles.
Mathematics
2 answers:
zhannawk [14.2K]3 years ago
7 0

Answer:

(a)

2,155,120

(b)

225,060,000

(c)

251,720,000

Step-by-step explanation:

We have to write numerals for each of the italicized number word names found in these examples.

(a)

two million, one hundred fifty-five thousand, one hundred twenty =

2,155,120

( since 1 million could be represented as:

1\times 10^6

so 2 million could be written as:

2\times 10^6

similarly one hundred fifty-five thousand is written aS:

155000

and one hundred twenty is written as 120.

Hence, the number  two million, one hundred fifty-five thousand, one hundred twenty  is written aS:

2,155,120 )

similarly we could proceed for (b) and (C) option.

(b)

two hundred twenty-five million, sixty thousand =

225,060,000

(c)

two hundred fifty-one million, seven hundred twenty thousand =

251,720,000



Juli2301 [7.4K]3 years ago
3 0
It is not really difficult writing numerals if you have only their word names - just make sure you know how many numbers a million consists of, a thousand, etc.
A. two million, one hundred fifty-five thousand, one hundred twenty =
2,155,120
B. two hundred twenty-five million, sixty thousand =
225,060,000
C. two hundred fifty-one million, seven hundred twenty thousand =
251,720,000
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Data is collected to compare two different types of batteries. We measure the time to failure of 12 batteries of each type. Batt
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Using the t-distribution, it is found that since the <u>test statistic is greater than the critical value for the right-tailed test</u>, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

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H_0: \mu_B - mu_A \leq 2

At the alternative hypothesis, it is <u>tested if it outlasts by more than 2 hours</u>, that is:

H_1: \mu_B - \mu_A > 2

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Hence, the standard errors are:

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The distribution of the difference has <u>mean and standard deviation</u> given by:

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s = \sqrt{s_{Ea}^2 + s_{Eb}^2} = \sqrt{0.1934^2 + 0.1934^2} = 0.2735

The test statistic is given by:

t = \frac{\overline{x} - \mu}{s}

In which \mu = 2 is the value tested at the hypothesis.

Hence:

t = \frac{\overline{x} - \mu}{s}

t = \frac{2.58 - 2}{0.2735}

t = 2.12

The critical value for a <u>right-tailed test</u>, as we are testing if the subtraction is greater than a value, with a <u>0.05 significance level</u> and 12 + 12 - 2 = <u>22 df</u> is given by t^{\ast} = 1.71

Since the <u>test statistic is greater than the critical value for the right-tailed test</u>, it is found that there is enough evidence to conclude that Battery B outlasts Battery A by more than 2 hours.

A similar problem is given at brainly.com/question/13873630

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