There are 7 more quarters than nickels. If there is a total of $ 2.65 in coins, how many quarters are there?

Mathematics

1 answer:

Solnce55 [7]3 years ago

5 0

o=nickel

O=quarter

O O O O O O O O O O + o o o =2.65

(2.50+.15=2.65)

there are 10 quarters total, and 3 nickels

You might be interested in

The radius of a circle is 2.9 in. Find the circumference to the nearest tenth (help please)

nika2105 [10]

Answer:4.18

Step-by-step explanation:

2.9+2/9

4 0

3 years ago

Read 2 more answers

Increase £40 by 5percent

natulia [17]

40(105/100)=42
.........................

5 0

3 years ago

Solve for y, show your steps<br><br><br>y = x(2y - 3)

Xelga [282]

Answer:

y= $\frac{-3x}{-2x+1}$

Step-by-step explanation:

3 0

3 years ago

Leave answer in the simplest radical form.

slega [8]

$\cfrac{7x^{-\frac{3}{2}} ~~ y^{\frac{5}{2}} ~~ z^{-\frac{2}{3}}}{56 x^{-\frac{1}{2}} ~~ y^{\frac{1}{4}}}\implies \cfrac{7}{56}\cdot \cfrac{y^{\frac{5}{2}} ~~ y^{-\frac{1}{4}}}{x^{-\frac{1}{2}} ~~ x^{\frac{3}{2}} ~~ z^{\frac{2}{3}}}\implies \cfrac{1}{8}\cfrac{y^{\frac{5}{2}-\frac{1}{4}}}{x^{-\frac{1}{2}+\frac{3}{2}}~~ z^{\frac{2}{3}}}$

$\cfrac{y^{\frac{9}{4}}}{8x z^{\frac{2}{3}}}\implies \cfrac{\sqrt[4]{y^9}}{8x\sqrt[3]{z^2}}\implies \cfrac{\sqrt[4]{y (y^2)^4}}{8x\sqrt[3]{z^2}}\implies \cfrac{y^2 \sqrt[4]{y}}{8x\sqrt[3]{z^2}}$

7 0

2 years ago

HELLLLLLLLPPPPPPPPPPPP!!!!!!

ICE Princess25 [194]

Answer:

3 bars of soap and 2 toothbrushes.

Step-by-step explanation:

4 0

4 years ago

Read 2 more answers