All categories

3 years ago

What is the solution to the following equation?

Mathematics

2 answers:

Deffense [45]3 years ago

7 0

Answer:

$- 26 + 6x = 6x - 24 - 2 = 6x - 26 \\ 0 = 0\\ x \: isall \: real \: number$

labwork [276]3 years ago

5 0

Answer:

B - x = all real numbers

Step-by-step explanation:

-26 + 6m = 6(m – 4)-2

-26 + 6m = 6m - 24 - 2

-26 + 6m = 6m - 26

+26 +26

------------------------------

6m = 6m

-6m -6m

-------------------------------

0 = 0

You might be interested in

A number to the 9th power divided by the same number to the 6th power equals 125. What is the

Gelneren [198K]

Answer:

Step-by-step explanation:

Let the required number be x

$\huge {x}^{9} \div {x}^{6} = 125 \\ \\ \huge {x}^{9 - 6} = 125 \\ \\ \huge {x}^{3} = 125 \\ \\ \huge x = \sqrt[3]{125} \\ \\ \huge x = \sqrt[3]{ {5}^{3} } \\ \\ \huge \red{ x = 5}$

7 0

4 years ago

Factor Completely 8x^2-8xy-6y^2

IRISSAK [1]

Answer:

8x2−8xy−6y2

Step-by-step explanation:

if your answer choices contain exponents then of course the number behind the x's are exponents.

4 0

3 years ago

Plzzz I need help with this question I tried to solve it many times but I can't

blsea [12.9K]

Answer and Step-by-step explanation: Area of a right triangle, (as any other triangle), is calculated as: $A1=\frac{(base)(height)}{2}$

Area of a rectangle is calculated as: $A2=(side)(side)$

Area of a right trapezoid is: $A3=\frac{(a+b)h}{2}$ , where:

a is short base

b is long base

h is height

1) Expressing areas in terms of x:

Area of triangle S1:

$S1=\frac{(2x-3)(4x-6)}{2}$

$S1=4x^{2}-12x+9$

Area of rectangle S2:

$S2 = (4x-6)(3x-2)$

$S2=12x^{2}-26x+12$

Area of trapezoid S3:

$S3=\frac{(2x+3+4x+1)(2x-3)}{2}$

$S3=\frac{(6x+4)(2x-3)}{2}$

$S3=6x^{2}-5x-6$

2) a) $S=4x^{2}-12x+9+12x^{2}-26x+12-(6x^{2}-5x-6)$

$S=4x^{2}-12x+9+12x^{2}-26x+12-6x^{2}+5x+6$

$S=10x^{2}-33x+37$

Which is the same as S = (2x-3)(5x-9)

b) For the areas to be the same:

$\frac{(3x-2+3x-2+2x-3)(4x-6)}{2}=\frac{(6x+4)(2x-3)}{2}$

$\frac{(8x-7)(4x-6)}{2}=\frac{(6x+4)(2x-3)}{2}$

$32x^{2}-48x-28x+42=12x^{2}+8x-18x-12$

$20x^{2}-66x+54=0$

Using Bhaskara to solve the second degree equation:

$\frac{66+\sqrt{(-66)^{2}-(4.20.54)} }{2(20)}$

$x_{1}=\frac{66+6}{40}$ = 1.8

$x_{2}=\frac{66-6}{40}$ = 1.5

For the areas of AFGC and ADEB to be equal, x has to be 1.5 or 1.8.

c) Expand a polynomial (or equation) is to multiply all the terms, remiving the parenthesis. Reduce a polynomial (or equation) is to combine terms alike,e.g.:

$S=(2x-3)(5x-9)$

$S=10x^{2}-18x-15x+27$ (expand)

$S=10x^{2}-33x+27$ (reduce)

d) For area of AFCG to be bigger than area of ADEB by 27:

$32x^{2}-48x-28x+42=12x^{2}+8x-18x-12+27$

$32x^{2}-48x-28x+42=12x^{2}+8x-18x+15$

$20x^{2}-66x+27=0$

Solving:

$\frac{66+\sqrt{(-66)^{2}-(4.20.27)} }{2(20)}$

$\frac{66+46.86}{40}$

$x_{1}=\frac{66+46.86}{40}=$ 2.82

$x_{2}=\frac{66-46.86}{40}$ = 0.48

According to the enunciation, x cannot be less than 1.5, then, the value of x so that area AFGC exceeds the area ADEB by 27 is 2.82

6 0

3 years ago

What is the slope of the line shown below?

marta [7]

Answer:

i think is A

Step-by-step explanation:

4 0

3 years ago

Read 2 more answers

Solve the following equation. Then place the correct number in the box provided. x/8=.42

Anuta_ua [19.1K]

Answer: 3.36

Step-by-step explanation:

hello. My name is Mary. I am in 7th grade.

So On the left side you see that it is division so you do the inverse operation which is multiplication. You cross out x/8 and go to the right side . .42 times 8 s 3.36. X=3.36.

6 0

3 years ago