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evablogger [386]
3 years ago
8

Bill sold 75 tickets for a Naked Season gig. he sold x £5 tickets and y £8 tickets. He collected £444. How many of each type of

ticket did he sell?
Mathematics
1 answer:
Ber [7]3 years ago
4 0

Answer:  £5 = 52 tickets,  £8 = 23 tickets

<u>Step-by-step explanation:</u>

                      Quantity        Cost

£5 Tickets           x                 5x

<u>£8 Tickets   </u>   <u>     y        </u>     <u>    8y    </u>

    TOTAL          75               444

  Cost:     5x + 8y = 444   →  1(5x + 8y = 444)   →    5x + 8y = 444

Quantity:    x +   y =   75   → -5( x +   y =   75)    →  <u> -5x - 5y</u> = <u>-375</u>

                                                                                         3y =  69

                                                                                           y = 23

Input y = 23 into one of the original equations to solve for x:

x +  y  = 75

x + 23 = 75

x         = 52

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Answer:

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Step-by-step explanation:

2x + 2k = m, right?

So, to bring 2k alone, we'll subtract 2x.

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Now, we'll divide both sides by 2! ^ _ ^

k = (m - 2x) / 2

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P(X&lt; ) 1-P(X&gt; ) A softball pitcher has a 0.626 probability of throwing a strike for each curve ball pitch. If the softball
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Answer:

19.49% probability that no more than 16 of them are strikes

Step-by-step explanation:

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Normal probability distribution

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In this problem, we have that:

n = 30, p = 0.626

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What is the probability that no more than 16 of them are strikes?

Using continuity correction, this is P(X \leq 16 + 0.5) = P(X \leq 16.5), which is the pvalue of Z when X = 16.5. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{16.5 - 18.78}{2.65}

Z = -0.86

Z = -0.86 has a pvalue of 0.1949

19.49% probability that no more than 16 of them are strikes

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