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2 years ago

PLLKEEASE HELPPPPPPP ASAPP

Mathematics

1 answer:

erica [24]2 years ago

7 0

Answer:

x = 19

Step-by-step explanation:

(5x + 4)° + (x - 2)° + (3x + 7)° = 180°

(5x + x + 3x)° + (4 - 2 + 7)° = 180°

9x° + 9° = 180° → ÷9

x + 1 = 20

x = 20 - 1

x = 19

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You have a rather strange die: Three faces are marked with the letter A, two faces with the letter B, and one face with the lett

Gnesinka [82]

Answer:

8/27 ≈ 29.6%

Step-by-step explanation:

Two of the six faces are B, which means four of the six faces are not B.

The probability of rolling not B three times is:

P = (4/6)^3

P = (2/3)^3

P = 8/27

P ≈ 29.6%

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3 years ago

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Intersection point of Y=logx and y=1/2log(x+1)

GalinKa [24]

Answer:

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

The Problem:

What is the intersection point of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ ?

Step-by-step explanation:

To find the intersection of $y=\log(x)$ and $y=\frac{1}{2}\log(x+1)$ , we will need to find when they have a common point; when their $x$ and $y$ are the same.

Let's start with setting the $y$ 's equal to find those $x$ 's for which the $y$ 's are the same.

$\log(x)=\frac{1}{2}\log(x+1)$

By power rule:

$\log(x)=\log((x+1)^\frac{1}{2})$

Since $\log(u)=\log(v)$ implies $u=v$ :

$x=(x+1)^\frac{1}{2}$

Squaring both sides to get rid of the fraction exponent:

$x^2=x+1$

This is a quadratic equation.

Subtract $(x+1)$ on both sides:

$x^2-(x+1)=0$

$x^2-x-1=0$

Comparing this to $ax^2+bx+c=0$ we see the following:

$a=1$

$b=-1$

$c=-1$

Let's plug them into the quadratic formula:

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{1 \pm \sqrt{(-1)^2-4(1)(-1)}}{2(1)}$

$x=\frac{1 \pm \sqrt{1+4}}{2}$

$x=\frac{1 \pm \sqrt{5}}{2}$

So we have the solutions to the quadratic equation are:

$x=\frac{1+\sqrt{5}}{2}$ or $x=\frac{1-\sqrt{5}}{2}$ .

The second solution definitely gives at least one of the logarithm equation problems.

Example: $\log(x)$ has problems when $x \le 0$ and so the second solution is a problem.

So the $x$ where the equations intersect is at $x=\frac{1+\sqrt{5}}{2}$ .

Let's find the $y$ -coordinate.

You may use either equation.

I choose $y=\log(x)$ .

$y=\log(\frac{1+\sqrt{5}}{2})$

The intersection is $(\frac{1+\sqrt{5}}{2},\log(\frac{1+\sqrt{5}}{2})$ .

6 0

3 years ago

Suppose AC = 48, find the value of x. Then, find the length of AB and the length of BC.<br> 1

gladu [14]

Answer:

2x-4+3x+2=48

5x-2=48

5x=48+2

5x=50

x=10

Step-by-step explanation:

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3 years ago

Please answer question with work ♥️

vova2212 [387]

Answer:

r=201

d = 77 1/2

Step-by-step explanation:

6) First multiply left and right by 16, to get rid of the fraction:

r - 25 = 11*16

Now add 25 left and right:

r = 11*16 + 25 = 201

7) Add 5 left and right

2/5 d = 31

multiply by 5/2

d = 31 * 5/2 = 77 1/2

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3 years ago

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rewona [7]

Answer:

Graph D.

Step-by-step explanation:

The line goes through the origin, and therefore shows direct variation.

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3 years ago

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