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3 years ago

If f(x) = (1/9)(9^x) what is f(3)

Mathematics

2 answers:

TiliK225 [7]3 years ago

8 0

Answer: The required value of f(3) is 81.

Step-by-step explanation: We are given the following function :

$f(x)=\left(\dfrac{1}{9}\right)9^x~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~(i)$

We are to find the value of f(3).

Substituting x = 3 in equation (i), we get

$f(3)\\\\\\=\left(\dfrac{1}{9}\right)\times9^3\\\\=9^2\\\\=81.$

Thus, the required value of f(3) is 81.

pochemuha3 years ago

3 0

Answer:

Step-by-step explanation:

APEX

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PLEASE HELP! Solve the open sentence. 8 < 2b or 2b + 15 < 5

SIZIF [17.4K]

The answer: b>4 or b<−5

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Step-by-step explanation:

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2 years ago

The seasonal output of a new experimental strain of pepper plants was carefully weighed. The mean weight per plant is 15.0 pound

DanielleElmas [232]

Answer:

There are 118 plants that weight between 13 and 16 pounds

Step-by-step explanation:

For any normal random variable X with mean μ and standard deviation σ : X ~ Normal(μ, σ)

This can be translated into standard normal units by :

$Z = \frac{(X - \mu)}{\sigma}$

Let X be the weight of the plant

X ~ Normal( 15 , 1.75 )

To find : P( 13 < X < 16 )

$= P(\frac{( 13 - 15 )}{1.75} < Z < \frac{( 16 - 15 )}{1.75})$

= P( -1.142857 < Z < 0.5714286 )

= P( Z < 0.5714286 ) - P( Z < -1.142857 )

= 0.7161454 - 0.1265490

= 0.5895965

So, the probability that any one of the plants weights between 13 and 16 pounds is 0.5895965

Hence, The expected number of plants out of 200 that will weight between 13 and 16 = 0.5895965 × 200

= 117.9193

Therefore, There are 118 plants that weight between 13 and 16 pounds.

4 0

3 years ago

Simplify the following expression (6x2 + 8x - 3) - (3x2 - 6)

Vsevolod [243]

Answer:

3x^2 +8x +3

Step-by-step explanation:

(6x^2 + 8x - 3) - (3x^2 - 6)

Distribute the minus sign

(6x^2 + 8x - 3) - 3x^2 + 6

Combine like terms

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2 years ago

6 children and 2 adults are going to the circus, children tickets are on sale, half the price of adult tickets totaling $54. How

inna [77]

Answer:

Price of 1 child ticket is $5.4

Price of 1 adult ticket is $10.8

Step-by-step explanation:

Given:-

6 children and 2 adults are going for circus.

Children ticket is half the price of adult ticket.

Total ticketing cost =$54

To find:-

Cost of 1 child ticket=?

Cost of 1 Adult ticket=?

Solution:-

Let price of 1 child ticket be x and price of 1 adult ticket be y,

therefore from the given data we get 2 equations,

$6x+2y=54$ -----------------------------------(1)

$x=\frac{1}{2} y$ --------------------------------(2)

Now, substituting the value of x from equation 2 in equation 1,

$6x+2y=54$

$6(\frac{1}{2} y)+2y=54$

$\frac{6}{2}y+2y=54$

$3y+2y=54$

$5y=54$

$\therefore y=\frac{54}{5}$

$\therefore y =10.8$ ------------------------(3)

Now, substituting the value of y from equation 3 in equation 2,

$x=\frac{1}{2} y$

$\therefore x=\frac{1}{2} \times 10.8$ ------------(from equation 3)

$\therefore x=\frac{10.8}{2}$

$\therefore x=5.4$ ----------------------(4)

As, x is price of 1 child ticket and y is price of 1 adult ticket,

Therefore price of 1 child ticket is $5.4 and price of 1 adult ticket is $10.8

7 0

3 years ago