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3 years ago

Recall that two angles are complements of each other if

Mathematics

1 answer:

lbvjy [14]3 years ago

4 0

Angle 1: 33, Angle 2: 147

Step-by-step explanation:

If I have angle x, and its supplement angle is 3 times its supplement increased by 48 degrees, then I know the following:

Angle 1 = x

Angle 2 = 3x+48

Both of these angles add to 180 degrees.

x+(3x+48)=180

= 4x+48=180

=4x=132

=x=33, Angle 1 = 33 degrees

So angle 1 is 33 degrees

that should mean that angle 2 is 147

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Given one factor of the polynomial, factor the polynomial completely.

astraxan [27]

Answer:

The factors are (x - 1)(x - 5)(x + 2).

Step-by-step explanation:

Long division:

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x^3 - 5x^2

x^2 - 7x

x^2 - 5x

- 2x + 10

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...........

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3 years ago

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A basketball was originally priced at $25, but Tucker waited to buy it until the basketball was on sale for 20% off. If he paid

kotegsom [21]

Answer:

The answer to your question is $21.0

Step-by-step explanation:

Data

Original price = $25

Discount = 20%

Taxes = 5%

Process

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x ------------------- 20%

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x = 500 / 100

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3 0

3 years ago

The Resource Conservation and Recovery Act mandates the tracking and disposal of hazardous waste produced at U.S. facilities. Pr

aniked [119]

Answer:

(a) $E(X) = 0.383$

The expected number in the sample that treats hazardous waste on-site is 0.383.

(b) $P(x = 4) = 0.000169$

There is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

Step-by-step explanation:

Professional Geographer (Feb. 2000) reported the hazardous waste generation and disposal characteristics of 209 facilities.

N = 209

Only eight of these facilities treated hazardous waste on-site.

r = 8

a. In a random sample of 10 of the 209 facilities, what is the expected number in the sample that treats hazardous waste on-site?

n = 10

The expected number in the sample that treats hazardous waste on-site is given by

$E(X) = \frac{n \times r}{N}$

$E(X) = \frac{10 \times 8}{209}$

$E(X) = \frac{80}{209}$

$E(X) = 0.383$

Therefore, the expected number in the sample that treats hazardous waste on-site is 0.383.

b. Find the probability that 4 of the 10 selected facilities treat hazardous waste on-site

The probability is given by

$P(x = 4) = \frac{\binom{r}{x} \binom{N - r}{n - x}}{\binom{N}{n}}$

For the given case, we have

N = 209

n = 10

r = 8

x = 4

$P(x = 4) = \frac{\binom{8}{4} \binom{209 - 8}{10 - 4}}{\binom{209}{10}}$

$P(x = 4) = \frac{\binom{8}{4} \binom{201}{6}}{\binom{209}{10}}$

$$ P(x = 4) = \frac{70 \times 84944276340}{35216131179263320}$

$P(x = 4) = 0.000169$

Therefore, there is a 0.000169 probability that 4 of the 10 selected facilities treat hazardous waste on-site.

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3 years ago

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Kazeer [188]

Answer:

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