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Firlakuza [10]
3 years ago
6

Recall that two angles are complements of each other if

Mathematics
1 answer:
lbvjy [14]3 years ago
4 0

Angle 1: 33, Angle 2: 147

Step-by-step explanation:

If I have angle x, and its supplement angle is 3 times its supplement increased by 48 degrees, then I know the following:

Angle 1 = x

Angle 2 = 3x+48

Both of these angles add to 180 degrees.

x+(3x+48)=180

= 4x+48=180

=4x=132

=x=33, Angle 1 = 33 degrees

So angle 1 is 33 degrees

that should mean that angle 2 is 147

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I really don’t understand this and just need an explanation of how to do it.
sertanlavr [38]

\bf ~\hspace{12em}\left( \cfrac{2n}{-3n\cdot -2n^2} \right)^4
\\\\[-0.35em]
\rule{34em}{0.25pt}\\\\
\cfrac{2n}{-3n\cdot -2n^2}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{-2n^2}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{2n\cdot -n}\implies \cfrac{1}{-3n}\cdot \cfrac{2n}{2n}\cdot \cfrac{1}{-n}


\bf \cfrac{1}{-3n}\cdot \boxed{1}\cdot \cfrac{1}{-n}\implies \cfrac{1}{-3n\cdot -n}\implies \cfrac{1}{3n^2}
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\left( \cfrac{2n}{-3n\cdot -2n^2} \right)^4\implies \left( \cfrac{1}{3n^2} \right)^4\implies \stackrel{\textit{distributing the exponent}}{\cfrac{1^4}{3^4n^{2\cdot 4}}}\implies \cfrac{1}{81n^8}

7 0
3 years ago
What multiplies to -10000 and adds up to 0?
aleksley [76]
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3/4 divided by 5/6? i need the answer for this mobymax thing if i dont gets it done, im screwed
Dovator [93]
I believe it’s 0.9, or 9/10.
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3 years ago
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olga nikolaevna [1]

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Step-by-step explanation:

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3 years ago
Assume the population has a normal distribution. A sample of 25 randomly selected students Has a mean test score of 81.5 With a
Natasha_Volkova [10]

Answer:

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

Step-by-step explanation:

We have the standard deviation for the sample, so we use the t-distribution to solve this question.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 25 - 1 = 24

90% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 24 degrees of freedom(y-axis) and a confidence level of 1 - \frac{1 - 0.9}{2} = 0.95. So we have T = 2.064

The margin of error is:

M = T\frac{s}{\sqrt{n}} = 2.064\frac{10.2}{\sqrt{25}} = 4.21

In which s is the standard deviation of the sample and n is the size of the sample.

The lower end of the interval is the sample mean subtracted by M. So it is 81.5 - 4.21 = 77.29

The upper end of the interval is the sample mean added to M. So it is 81.5 + 4.21 = 85.71.

The 90% confidence interval for the mean test score is between 77.29 and 85.71.

6 0
3 years ago
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