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Jlenok [28]
3 years ago
11

What is the total number of moles of atoms in one mole of (NH4)2SO4? 1. 10 2. 11 3. 14 4. 15

Chemistry
2 answers:
anygoal [31]3 years ago
6 0

2N
8H
1S
4O
2+8+1+4=15

4.  15
Neporo4naja [7]3 years ago
5 0

Answer:

4. 15

Explanation:

The given formula is:- (NH_4)_2SO_4

1 mole of the salt contains 2 moles of nitrogen atom, 8 moles of hydrogen, 1 mole of sulfur and 4 moles of oxygen atom as can be seen from the formula.

Thus,

1 mole of salt contains total of 15 moles of the atoms which constitute the salt.

<u>Hence, 4. is the answer.</u>

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3 years ago
If the prescribed dosage of milk of magnesia Mg(OH)2 is 3.5 moles, how many grams
OlgaM077 [116]

Answer:

B

Explanation:

1 mole is equal to 58.31968 grams.

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3 0
3 years ago
If 0.60 L of a solution contains 6.6 g of NaBr, what is its molar concentration?
-BARSIC- [3]

Answer:

Molarity = moles ÷ liters

to get moles of NaBr divide grams of NaBr by its molar mass (mass of Na + mass of Bromine)

Na = 22.989769

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7 0
3 years ago
QUESTION 3 (a) Ammonium sulphate, (NH),50, is a soluble salt and it is used in agriculture as fertiliser. 5 g of ammonium sulpha
nataly862011 [7]

Answer:

The equation: (NH₄)₂SO₄ = 2NH4(+) + SO4(-2)

The number of moles = 5 g / 132.14 g/mol = 0.038 mol

The number of molecules = 0.038 X 6.022x10^23 = 2.29x10^23

the number of positive ions present in the ammonium sulphate solution:

2 positive ions for every 1 molecule of (NH₄)₂SO₄

so 2 x 2.29x10^23 = 4.58x10^23

the number of negative ions present in the ammonium sulphate solution

1 negative ion for every 1 molecule of (NH₄)₂SO₄

so 1 x 2.29x10^23 = 2.29x10^23

the total number of ions present in the ammonium sulphate solution​

4.58x10^23 + 2.29x10^23 = 6.87x10^23

4 0
3 years ago
What is the percent by mass of water in Na2SO4 • 10H2O?
bulgar [2K]
We determine the percent by mass of water in the compound by dividing the mass of  water by the total mass. The total mass of Na2SO4.10H2O is equal to 322 g. The mass of water is 180 g. 
       
                    percent by mass of water = (180 / 322)*(100 %) = 55.9%
5 0
3 years ago
Read 2 more answers
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