Answer:
The answer to your question is The honda civic hybrid weights 13181.8 N or 1318.2 kg
Explanation:
Data
Weight = 2900 lb
Weight = ? N
mass = ? kg
1 kg ------- 10 N
0.22lb ---- 1N
Use proportions to solve this problem
0.22 lb ------------------- 1 N
2900 lb ----------------- x
x = (2900 x 1) / 0.22
x = 2900 / 0.22
x = 13181.8 N
1 kg ----------------------- 10 N
x ----------------------- 13181.8 N
x = (13181.8 x 1)/10
x = 1318.2 kg
Answer:
3.33 tanques de O₂
Explanation:
Basados en la reacción:
2C₂H₂(g) + 5O₂(g) → 4CO₂(g) + 2H₂O(g)
<em>2 moles de acetileno reaccionan con 5 moles de oxígeno produciendo 4 moles de dióxido de carbono y 2 moles de agua</em>
<em />
La ley de Avogadro dice que el volumen de un gas bajo temperatura y presión constantes es proporcional a las moles de este gas. Así, como 2 moles de acetileno reaccionan con 5 moles de oxígeno, los litros de O₂ necesarios para quemar 9340L de acetileno son:
9340 L C₂H₂ × (5 moles O₂ / 2 moles C₂H₂) = <em>23350L de O₂</em>
Si un tanque contiene 7x10³ L de O₂ serán necesarios:
23350L O₂ ₓ (1 tanque / 7x10³L) =<em> 3.33 tanques de O₂</em>
Nitrogen atom has a valence electrons of 5 electrons. A full octet or full valence electrons shell is composed of 8 electrons. Hence, an additional of 4 electrons are needed for it to become full. this is achieved by covalent bonding where electrons are shared or ionic bonding where electrons are transferred.
The half-life of this radioisotope : 12 hr
<h3>Further explanation
</h3>
The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.
Usually radioactive elements have an unstable atomic nucleus.
General formulas used in decay:
t = duration of decay
t 1/2 = half-life
N₀ = the number of initial radioactive atoms
Nt = the number of radioactive atoms left after decaying during T time
t=48 hr
The half-life :
Answer: The energy of an electron depends on its location with respect to the nucleus of an atom. The higher the energy of an electron in an atom, the farther is its most probable location from the nucleus.
