Answer: A thing that died a long time ago, and it's bones were preserved in the ground.
Explanation:
Because yes
The molecular formula of the compound that we are required to find is the compound C4H8O8
<h3>What is empirical formula?</h3>
The empirical formula of a compound is a formula that shows the ratio of each atom present in the compound. We will start by dividing each mass with the relative atomic mass of the atom.
Carbon - 48.38 g/12 Hydrogen - 6.74 g/1 Oxygen - 53.5 g/16
Carbon - 4 Hydrogen - 6.74 Oxygen - 8.9
Dividing through by the lowest ratio;
Carbon - 4/4 Hydrogen - 6.74/4 Oxygen 8.9/4
Carbon 1 Hydrogen 2 Oxygen 2
The empirical formula is CH2O2.
To obtain the molecular formula; brainly.com/question/11588623
[12 + 2 + 32]n = 180
n = 180/[12 + 2 + 32]
n =4
The compound C4H8O8
Learn more about empirical formula:
Answer:
B. They both contain three atoms around the central atom.
Explanation:
Do the unit test on edg20 and got it right!
Answer:
Atomic radius of sodium = 227 pm
Atomic radius of potassium = 280 pm
Explanation:
Atomic radii trend along group:
As we move down the group atomic radii increased with increase of atomic number. The addition of electron in next level cause the atomic radii to increased. The hold of nucleus on valance shell become weaker because of shielding of electrons thus size of atom increased.
Consider the example of sodium and potassium.
Sodium is present above the potassium with in same group i.e, group one.
The atomic number of sodium is 11 and potassium 19.
So potassium will have larger atomic radius as compared to sodium.
Atomic radius of sodium = 227 pm
Atomic radius of potassium = 280 pm
Answer:
0.071L
Explanation:
From the question given, we obtained the following data:
Molarity of HCl = 2.25 M
Mass of HCl = 5.80g
Molar Mass of HCl = 36.45g/mol
Number of mole of HCl =?
Number of mole = Mass /Molar Mass
Number of mole of HCl = 5.8/36.45 = 0.159mole
Now, we can obtain the volume required as follows:
Molarity = mole /Volume
Volume = mole /Molarity
Volume = 0.159mole/ 2.25
Volume = 0.071L
