I need help 5,6,7,8,9,10,11,12,13,14,15,16 to rounding

Find all values of c such that c/(c - 5) = 4/(c - 4). If you find more than one solution, then list the solutions you find separ

Deffense [45]

Answer:

$\large\boxed{\bold{NO\ REAL\ SOLUTIONS}}\\\boxed{x=4-2i,\ x=4+2i}$

Step-by-step explanation:

$Domain:\\c-4\neq0\ \wedge\ c-5\neq0\Rightarrow c\neq4\ \wedge\ c\neq5\\\\\dfrac{c}{c-5}=\dfrac{4}{c-4}\qquad\text{cross multiply}\\\\c(c-4)=4(c-5)\qquad\text{use the distributive property}\\\\c^2-4c=4c-20\qquad\text{subtract}\ 4c\ \text{from both sides}\\\\c^2-8c=-20\qquad\text{add 20 to both sides}\\\\c^2-8c+20=0\qquad\text{use the quadratic formula}$

$\text{for}\ ax^2+bx+c=0\\\\\text{if}\ b^2-4ac0,\ \text{then the equation has two solutions}\ x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}$

$x^2-8x+20=0\\\\a=1,\ b=-8,\ c=20\\\\b^2-4ac=(-8)^2-4(1)(20)=64-80=-16$

$\text{In the set of complex numbers:}\\\\i=\sqrt{-1}\\\\\text{therefore}\ \sqrt{b^2-4ac}=\sqrt{-16}=\sqrt{(16)(-1)}=\sqrt{16}\cdot\sqrt{-1}=4i\\\\x=\dfrac{-(-8)\pm4i}{2(1)}=\dfrac{8\pm4i}{2}=\dfrac{8}{2}\pm\dfrac{4i}{2}=4\pm2i$

6 0

2 years ago

Read 2 more answers

AVERAGES 1. Find the mean, mode and median of: (a) 1.5, 1.2, 1.3, 1.5, 1.4 (b) 2.3, 1.2, 2.4, 1.2

NNADVOKAT [17]

Answer:

Look at Step by step

Step-by-step explanation:

Mean: (a) 1.38

Mean: (b) 1.7

median (a) 1.3

Pacx '?

a]g.;//

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[c' / v\Zcccccccc

8 0

3 years ago

Read 2 more answers

(a) find the general solution to y^{\,\prime\prime} + 3 y^{\,\prime} = 0. give your answer as y = . . . \ . in your answer, use

KengaRu [80]

We want to solve
y'' + 3y' = 0

Solve the indicial equation.
m² + 3m = 0
m(m + 3) = 0
m = 0 or m = -3

The basic solutions are e⁰=1 and $e^{-3x}$ .

Answer:
The general solution is
$y(x) = c_{1} + c_{2}e^{-3x}$

4 0

3 years ago

Jerome spent $20 on supplies to make 50 cookies for a bake sale. Write and solve an inequality to find the price that Jerome sho

Semenov [28]

Answer:

Each cookie will have to be sold for at least $0.90 if the profit is to be made is more than $25.

Step-by-step explanation:

The amount spent on supplies is $20.

The number of cookies baked is = 50.

If the profit to be made is more than $25.00 .

Then we can safely say that all the cookies have to be sold for

= $20.00 + $25.00

= $45.00

Therefor the required inequality can be written as

50 x ≥ $45.00 ⇒ x ≥ $\frac{45.00}{50}$ ⇒ x ≥ $0.90.

Therefore we can say that each cookie will have to be sold for at least $0.90 if the profit is to be made is more than $25.

7 0

3 years ago

Use the diagram to complete the statement.

Elanso [62]

75° because they are alternate interior angles

3 0

3 years ago