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Dominik [7]
3 years ago
6

How many meters are in .678 killometers

Mathematics
2 answers:
olchik [2.2K]3 years ago
8 0
There are 678 meters inkilometersmeters
TEA [102]3 years ago
7 0
.678 kilometers is equal to 678 meters.
1 kilometers = 1,000 meters.
To get this answer, it's pretty simple.
1.000km = 1000m
So .678km = 678m.
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HELP! Look at the stem-and-leaf plot. What is the mode of the numbers?
puteri [66]
The answer is 100
since the number 100 is the number that appears to be the most frequent
7 0
2 years ago
The number of accidents that occur at a busy intersection is Poisson distributed with a mean of 4.5 per week. Find the probabili
Mariana [72]

Answer:

a) 0.01111

b) 0.4679

c) 0.33747

Step-by-step explanation:

We are given the following in the question:

The number of accidents per week can be treated as a Poisson distribution.

Mean number of accidents per week = 4.5

\lambda= 4.5

Formula:

P(X =k) = \displaystyle\frac{\lambda^k e^{-\lambda}}{k!}\\\\ \lambda \text{ is the mean of the distribution}

a) No accidents occur in one week.

P(x =0)\\\\= \displaystyle\frac{4.5^0 e^{-4.5}}{0!}= 0.01111

b) 5 or more accidents occur in a week.

P( x \geq 5) = 1-\displaystyle \sum P(x

c) One accident occurs today.

The mean number of accidents per day is given by

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P(x =1)\\\\= \displaystyle\frac{0.64^1 e^{-0.64}}{1!}= 0.33747

5 0
3 years ago
Find the sum of the first 42 terms of the following series, to the nearest
balandron [24]

Answer:

Step-by-step explanation:

Find the sum of the first 42 terms of the following series, to the nearest integer.

2,7,12

Solution

The sum is given by  

SUM_n=n/2*(a_1+a_n)

a_n=a_1+(n-1)d

a_1=2,   n=42,     d=5

The 42nd term is therefore given by  

a_42=2+(42-1)5=207

SUM_42=42/2*(2+207)=21*209=4389

The sum of the first 42 terms of the series, therefore, is 4389

5 0
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Whatnis the gcf of 27 and 18
ch4aika [34]
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7 0
3 years ago
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What is 1 to 4 and 3 to 12?​
zloy xaker [14]

Answer:

1:4 and 3:12

Step-by-step explanation:

They are equivalent! Hope this helps! :)

7 0
2 years ago
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