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Temka [501]
3 years ago
5

If 0.22... < x <33 , which of the following could be the value of x?

Mathematics
1 answer:
masha68 [24]3 years ago
6 0

Answer:

Step-by-step explanation:

7

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Answer:

  a) 236/100 = 2.36

  b) 101/100 = 1.01

  c) 814/100 = 8.14

Step-by-step explanation:

The divisor in each case is already a factor of 100, so multiply the numerator and denominator by the number that will make the denominator 100. Then add 100 times the integer to the numerator of the fraction.

a) 2 9/25 = (200 +9·4)/(25·4) = 236/100 = 2.36

b) 1 1/100 = (100 +1)/100 = 101/100 = 1.01

c) 8 7/50 = (800 +7·2)/(50·2) = 814/100 = 8.14

____

Since each of these fractions has a denominator of 100, the decimal can be written by putting the least significant digit of the numerator in the hundredths place of the decimal number.

For example, for 236/100, putting 6 in the hundredths place puts 3 in the tenths place and 2 in the units place for a decimal number of 2.36.

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crimeas [40]

Answer:

The zeros are:

x =4, x=2, x = 5

  • The function has three distinct real zeros.

Hence, option (B) is true.

Step-by-step explanation:

Given the expression

h\left(x\right)=\left(x-4\right)^2\left(x^2-7x+\:10\right)

Let us determine the zeros of the function by putting h(x) = 0 and solving the expression

0=\left(x-4\right)^2\left(x^2-7x+10\right)

switch sides

\left(x-4\right)^2\left(x^2-7x+10\right)=0

as

x^2-7x+\:10=\left(x-2\right)\left(x-5\right)

so

\left(x-4\right)^2\left(x-2\right)\left(x-5\right)=0

Using the zero factor principle

  • \mathrm{If}\:ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

so

x-4=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x =4, x=2, x = 5

Thus, the zeros are:

x =4, x=2, x = 5

It is clear that there are three zeros and all the zeros are distinct real numbers.

Therefore,

  • The function has three distinct real zeros.

Hence, option (B) is true.

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2 years ago
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