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skad [1K]
3 years ago
15

In 1968, it cost $54,000 for a 30 second commercial during the super bowl. In 1973, the cost for a 30 second commercial was $88,

000. What is the percent increase, round to the nearest whole number, in the cost of a 30 second commercial from 1968 to 1973?
Mathematics
1 answer:
sukhopar [10]3 years ago
6 0

Answer:

you idiot are you joking

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According to a human modeling​ project, the distribution of foot lengths of women is approximately Normal with a mean of 23.4 ce
stiv31 [10]

Answer: 22.0.6%

Step-by-step explanation:

Given : According to a human modeling​ project, the distribution of foot lengths of women is approximately Normal with \mu=23.3\ cm and \sigma=1.3\ cm.

In the United​ States, a​ woman's shoe size of 6 fits feet that are 22.4 centimeters long.

Then, the probability that women in the United States will wear a size 6 or​ smaller :-

P(x\leq22.4)=P(z\leq\dfrac{22.4-23.4}{1.3})\ \ [\because z=\dfrac{x-\mu}{\sigma}]\\\\\approx P(z\leq-0.77)\\\\=1-P(z\leq0.77)\\\\=1-0.77935=0.2206499\approx0.2206=22.06\%

Hence,  the required answer = 22.0.6%

4 0
3 years ago
The spherical balloon is inflated at the rate of 10 m³/sec. Find the rate at which the surface area is increasing when the radiu
rjkz [21]

The balloon has a volume V dependent on its radius r:

V(r)=\dfrac43\pi r^3

Differentiating with respect to time t gives

\dfrac{\mathrm dV}{\mathrm dt}=4\pi r^2\dfrac{\mathrm dr}{\mathrm dt}

If the volume is increasing at a rate of 10 cubic m/s, then at the moment the radius is 3 m, it is increasing at a rate of

10\dfrac{\mathrm m^3}{\mathrm s}=4\pi (3\,\mathrm m)^2\dfrac{\mathrm dr}{\mathrm dt}\implies\dfrac{\mathrm dr}{\mathrm dt}=\dfrac5{18\pi}\dfrac{\rm m}{\rm s}

The surface area of the balloon is

S(r)=4\pi r^2

and differentiating gives

\dfrac{\mathrm dS}{\mathrm dt}=8\pi r\dfrac{\mathrm dr}{\mathrm dt}

so that at the moment the radius is 3 m, its area is increasing at a rate of

\dfrac{\mathrm dS}{\mathrm dt}=8\pi(3\,\mathrm m)\left(\dfrac5{18\pi}\dfrac{\rm m}{\rm s}\right)=\dfrac{20}3\dfrac{\mathrm m^2}{\rm s}

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The answer is x>−1/5 or x<1/5

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Gap sells jeans that cost $21.00 for a selling price of $29.95. The percent of markup based on cost is
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If Gap sells jeans that cost $21.00 for selling price of $29.95. The percent of markup based on cost is approximately 43%. The markup in price is exactly $8.95.
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Step-by-step explanation:

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