First you need to count the atoms of each element in the reactantsa and the products. Then use coefficients and place them in front of the compunds until the equations looks fully balanced.
Hope i helped
Answer:-
Solution:- If both acid and basic form are present at the same time then it's like a buffer solution since the buffer solution also has a weak acid and its conjugate base. The Handerson equation is used for solving buffer problems. Let's use the same equation here also.
The equation is:
pKa is given as 9.7 and the pH is 2.2. let's plug in the values in the equation.
subtract 9.7 from sides:
taking antilog:
So, the answer is .
The answer is c because of going left to right
The answer is force
sorry if i’m wrong
Answer:
- 12.1
Explanation:
M(C3H8O3) = 3*12.0 + 8*1.0 + 3*16.0 = 92 g/mol
210.0 g C3H8O3 * 1 mol C3H8O3/92 g C3H8O3 = 210/92 mol C3H8O3
350.g = 0.350 kg H2O
Molality = mol soluty/ kg solvent = (210/92 mol C3H8O3) /(0.350 kg H2O) = =6. 522 molal
ΔT =i* Kf* m
(T2 - T1) = i* Kf* m
(T2 - 0°C) = 1*(-1.86°C/molal *6.522 molal)
T2= - 12.1°C