Here, the rate of reaction would be: rate = k[A]
In short, Your Answer would be Option D
Hope this helps!
6 - one sodium atom, 1 hydrogen atom, 1 carbon atom, and 3 oxygen atoms.
Answer:
both are a number group of 12
Explanation:
dozen=12
The first thing you need to do is calculate the molar mass of C4H10. To do this, look at a periodic table for the atomic mass of carbon and hydrogen. For Hydrogen it's 1.008 amu. For Carbon its 12.01 amu. This means that a mole of hydrogen has a mass of 1.008 amu. So to calculate the molar mass of C4H10:
atomic mass of H * number of H atoms in one molecule + atomic mass of C * number of C atoms in one molecule
1.008 * 10 + 4 * 12.01
= 58.12 g
So one mole of C4H10 would have a mass of 58.12 g.
Now you were told to find the number of moles for 2.50 g, so you need to change 2.50g into moles
2.50g *1 mole/ 58.12 g = .043014 moles of C4H10
You know that for every mole of C4H10, there are 4 moles of Carbon
so
.043014 mole C4H10 * 4 mole C/1 mole C4H10 = .172 mol C
Now to find the number of atoms, use avogadros numbe5r
6.022 * 10^23 * .17 mol = 1.024 × 10^23 atoms your answer.The first thing you need to do is calculate the molar mass of C4H10. To do this, look at a periodic table for the atomic mass of carbon and hydrogen. For Hydrogen it's 1.008 amu. For Carbon its 12.01 amu. This means that a mole of hydrogen has a mass of 1.008 amu. So to calculate the molar mass of C4H10:
atomic mass of H * number of H atoms in one molecule + atomic mass of C * number of C atoms in one molecule
1.008 * 10 + 4 * 12.01
= 58.12 g
So one mole of C4H10 would have a mass of 58.12 g.
Now you were told to find the number of moles for 2.50 g, so you need to change 2.50g into moles
2.50g *1 mole/ 58.12 g = .043014 moles of C4H10
You know that for every mole of C4H10, there are 4 moles of Carbon
so
.043014 mole C4H10 * 4 mole C/1 mole C4H10 = .172 mol C
Now to find the number of atoms, use avogadros numbe5r
6.022 * 10^23 * .17 mol = 1.024 × 10^23 atoms your answer.
Hope it helps
