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aev [14]
3 years ago
14

Add: (8a5+2b) + (-6a5+2b)

Mathematics
1 answer:
ser-zykov [4K]3 years ago
3 0
(8a^5 +2b) + (-6a^5 +2b) = (2a^5 +4b)

hope so much that i ve understood it right theses fives are exponents of ,,a"
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Help me with this please
bekas [8.4K]

Answer:

f(-5) = 4(-5) + 1 = -20 + 1 = -19

f(-1) = 4(-1) + 1 = -4 + 1 = -3

f(2) = 4(2) + 1 = 8 + 1 = 9

f(3) = 4(3) + 1 = 12 + 1 = 13

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7 0
2 years ago
A soft-drink machine can be regulated so that it discharges an average of μ oz. per cup. If the ounces of fill are Normally dist
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Answer:

μ = 5.068 oz

Step-by-step explanation:

Normal distribution formula to use the table attached

Z = (x - μ)/σ

where μ is mean, σ is standard deviation, Z is on x-axis and x is a desired point.

98% of 6-oz. cups will not overflow means that the area below the curve is equal to 0.49; note that the curve is symmetrical respect zero, so, 98% of the cases relied between the interval (μ - some value) and (μ + some value)].

From table attached, area = 0.49 when Z = 2.33. From data, σ = 0.4 oz and x = 6 oz (maximum capacity of the cup). Isolating x from the formula gives

Z = (x - μ)/σ

2.33 = (6 - μ)/0.4

μ = 6 - 2.33*0.4

μ = 5.068

This means that with a mean of 5 oz and a standard deviation of 0.4 oz, the machine will discharge a maximum of 6 oz in the 98% of the cases.

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3 years ago
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