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3 years ago

Add: (8a5+2b) + (-6a5+2b)

Mathematics

1 answer:

ser-zykov [4K]3 years ago

3 0

(8a^5 +2b) + (-6a^5 +2b) = (2a^5 +4b)

hope so much that i ve understood it right theses fives are exponents of ,,a"

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How do you solve a scale factor?

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Basically you multiply the original length by the scale factor. So let's say there's a side length of 10 and the scale factor is .5, then you multiply 10 by .5 and get 5, that's all scale factor is . It can get larger/smaller, just depends on the number.

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3 years ago

The entire pink figure has been transformed to create the new blue image. Describe the transformation that has taken place.

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Answer:

D. (bottom right)

Step-by-step explanation:

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3 years ago

A survey found that women's heights are normally distributed with mean 63.3 in. and standard deviation 2.7 in. The survey also

mylen [45]

Answer:

A) There is a 100% chance of meeting the height requirement for women.

B) There is a 99.89% chance of meeting the height requirement for men.

C) New height requirements are:

71.9 inches for men and 58.9 inches minimum for women.

At least 58.9 inches and at most 71.9 inches.

Step-by-step explanation:

This question involves finding z values which tell us the percentage from 0 to x.

z = (x-μ)/σ

A) In this question, the minimum sample point is 4 ft 9 inches or converting to inches, we have;(4*12) + 9 =57 inches.

The maximum sample point is 6 ft 4 inches which in inches gives; (6*12) + 4 = 76 inches

For the minimum point;

z = (57 - 63.3)/2.7 = -2.33

From the z-distribution table, this equates to 0.0099.

The maximum;

z = (76 - 63.3)/2.7 = 4.70

From the z-table, it gives 0.999.. Basically 100%.

So there is a 100% chance of meeting the height requirement for women.

B) For men;

the minimum z = (57 - 67.3)/2.8 = -3.68 which gives 0.00012 from the z-distribution table.

The maximum;

z = (76 - 67.3)/2.8 = 3.07 which gives 0.9989 from the z-distribution table. Basically, 99.89%.

So there is a 99.89% chance of meeting the height requirement for men.

C) To exclude the tallest 5% of men, we need to find the z-value for 0.95 and then solve for x.

Thus from the z-table, z = 1.65. So;

1.645 = (x - 67.3)/2.8

4.606 = x - 67.3

x = 67.3 + 4.606

x ≈ 71.9 inches for men.

So, Current minimum is okay.

To exclude the shortest 5% of women, we need to find the z for 0.05.

From the z-distribution table, it has a value of -1.645. So;

-1.645 = (x - 63.3)/2.7

-4.4415 = x - 63.3

x = 63.3 - 4.4415

x ≈ 58.9 inches minimum.

So, Current maximum is okay.

5 0

3 years ago

Three less than one-fourth of the product of eight thirds and nine. Please write equation, then solve.

kenny6666 [7]

Put simply, you have to work backwards in making the equations. Start with the product of 8/3 and 9.
$\frac{8}{3}$ *9

Next take 1/4 of that. This can be done in two ways, either multiplying by 1/4:
( $\frac{8}{3}$ *9)* $\frac{1}{4}$

, or dividing everything by 4.
( $\frac{8}{3}$ *9)/4

Finally, subtract three.

The final equation would read:
(( $\frac{8}{3}$ *9)* $\frac{1}{4}$ )-3

Using PE(M/D)(A/S), we'd start with $\frac{8}{3}$ *9

3 and 9 cancel out to be 1 and 3, leaving us with $\frac{8}{1}$ , or 8, and 3 and this part of the equation reading 8*3, which is 24.

The next step is $\frac{24}{4}$ , which is 6.

Lastly we subtract 3 from six, leaving us 3.

7 0

3 years ago

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