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Dima020 [189]
4 years ago
9

X+y=12 x-y=2 Solve by elimination

Mathematics
1 answer:
FrozenT [24]4 years ago
7 0
x+y=12 \\
\underline{x-y=2} \\
x+x=12+2 \\
2x=14 \\
x=\frac{14}{2} \\
x=7 \\ \\
x+y=12 \\
7+y=12 \\
y=12-7 \\
y=5 \\ \\
\boxed{(x,y)=(7,5)}
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1. Kyle and John are twins who decided to plan an imaginary trip that started with cliff jumping. There were two different spots
Vikki [24]

Answer:

a) Δx = -35ft

b) Δx = -25ft

c) Kyle traveled 10ft more than John

Step-by-step explanation:

We define a coordinate reference system() in which y = 0 corresponds to the water surface.

a) The initial position of Kyle in our coordinate reference system is:

   x_{o} = 20 ft

   and his final position is:

   x_{f} = -15 ft

   Therefore, he traveled

   Δx = x_{f} - x_{o} = -15 - 20 = -35 ft

b) The initial position of John in our coordinate reference system is:

   x_{o} = 15 ft

   and his final position is:

   x_{f} = -10 ft

   Therefore, he traveled

   Δx = x_{f} - x_{o} = -10 - 15 = -25 ft

c) Then, Kyle traveled 10ft more than John

 

6 0
4 years ago
Write 12 ten thousands, 8 thousands,14 hundreds, 7 ones in standard form
Cloud [144]
<span><u><em>The correct answer is: </em></u>
129,407.

<u><em>Explanation</em></u><span><u><em>: </em></u>
12 ten-thousands = 12*10000=120,000.
8 thousands = 8*1000=8000;
<u>this gives us</u> 120,000+8,000=128,000.

14 hundreds = 14*100=1400;
<u>this gives us</u> 128,000+1,400=129,400.

7 ones = 7*1=7;
<u>this gives us</u> 129,400+7=129,407.</span></span>
7 0
4 years ago
Read 2 more answers
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4 0
4 years ago
Suppose that a spherical droplet of liquid evaporates at a rate that is proportional to its surface area: where V = volume (mm3
Alex

Answer:

V = 20.2969 mm^3 @ t = 10

r = 1.692 mm @ t = 10

Step-by-step explanation:

The solution to the first order ordinary differential equation:

\frac{dV}{dt} = -kA

Using Euler's method

\frac{dVi}{dt} = -k *4pi*r^2_{i} = -k *4pi*(\frac {3 V_{i} }{4pi})^(2/3)\\ V_{i+1} = V'_{i} *h + V_{i}    \\

Where initial droplet volume is:

V(0) = \frac{4pi}{3} * r(0)^3 =  \frac{4pi}{3} * 2.5^3 = 65.45 mm^3

Hence, the iterative solution will be as next:

  • i = 1, ti = 0, Vi = 65.45

V'_{i}  = -k *4pi*(\frac{3*65.45}{4pi})^(2/3)  = -6.283\\V_{i+1} = 65.45-6.283*0.25 = 63.88

  • i = 2, ti = 0.5, Vi = 63.88

V'_{i}  = -k *4pi*(\frac{3*63.88}{4pi})^(2/3)  = -6.182\\V_{i+1} = 63.88-6.182*0.25 = 62.33

  • i = 3, ti = 1, Vi = 62.33

V'_{i}  = -k *4pi*(\frac{3*62.33}{4pi})^(2/3)  = -6.082\\V_{i+1} = 62.33-6.082*0.25 = 60.813

We compute the next iterations in MATLAB (see attachment)

Volume @ t = 10 is = 20.2969

The droplet radius at t=10 mins

r(10) = (\frac{3*20.2969}{4pi})^(2/3) = 1.692 mm\\

The average change of droplet radius with time is:

Δr/Δt = \frac{r(10) - r(0)}{10-0} = \frac{1.692 - 2.5}{10} = -0.0808 mm/min

The value of the evaporation rate is close the value of k = 0.08 mm/min

Hence, the results are accurate and consistent!

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4 years ago
Read 2 more answers
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