Answer:
f'(x) = 2[3tan²(x)sec²(x) - 10csc⁴(x)cot(x)]
Step-by-step explanation:
f' of tan(x) = sec²(x)
f' of csc(x) = -csc(x)cot(x)
General Power Rule: uⁿ = xuⁿ⁻¹ · u'
Step 1: Write equation
2tan³(x) + 5csc⁴(x)
Step 2: Rewrite
2(tan(x))³ + 5(csc(x))⁴
Step 3: Find derivative
d/dx 2(tan(x))³ + 5(csc(x))⁴
- General Power Rule: 2 · 3(tan(x))² · sec²(x) + 5 · 4(csc(x))³ · -csc(x)cot(x)
- Multiply: 6(tan(x))²sec²(x) - 20(csc(x))³csc(x)cot(x)
- Simplify: 6tan²(x)sec²(x) - 20csc⁴(x)cot(x)
- Factor: 2[3tan²(x)sec²(x) - 10csc⁴(x)cot(x)]
Answer:
The value of the expression would be 11.
Step-by-step explanation:
3 (4 - n) + 8
When n = 3:
3 (4 - 3) + 8
3 (1) + 8
3 + 8
11
Answer: 76%
Step-by-step explanation:
each sq represents whole 5*5 = 25 for the second = 25 , but - the shaded area to find the unshaded are 25 - 13 = 12 unshaded square
50 = 100 , 50 - 12 = 38 shaded area in total
38*100/50 = ur answer
Step-by-step explanation:
Hope it helps.
Handwriting is a bit poor. So, restraint is advised!
:)
