It is formed at Divergent boundaries, two tectonic plates diverge from one another. New oceanic crust is being formed by hot molten rock slowly cooling and solidifying. The crust is very thin.
B is correct the births exceed deaths
Answer:
The most common interaction between alleles is a dominant/recessive relationship. An allele of a gene is said to be dominant when it effectively overrules the other (recessive) allele. Eye colour and blood groups are both examples of dominant/recessive gene relationships.
The main difference between dominant and recessive trait is that dominant genes always passes the dominant behavior genes while the recessive ones pass the recessive behavior genes. In fact, the dominant genes are said to be more likely to pass to future generations, while the recessive ones are less likely to do that.
Explanation:
The answer would be (A) Haploid Cells
Answer:
ΔG'° for the coupled reaction = -16.7 kJ/mol
<em>Note: The question is missing some parts. The complete question is as follows:</em>
<em>The first reaction in glycolysis is the phosphorylation of glucose:
</em>
<em>
Pi+glucose⟶glucose−6−phosphate+H2O
</em>
<em>This is a thermodynamically unfavorable process, with ΔG∘′= +13.8kJ/mol. In a liver cell at 37 ∘C the concentrations of both phosphate and glucose are normally maintained at about 5 mM each.</em>
<em>This very low concentration of the desired product would be unfavorable for glycolysis. In fact the reaction is coupled to ATP hydrolysis to give the overall reaction: ATP + glucose → glucose-6-phosphate + ADP + H+</em>
<em>What is the ΔG'° for the coupled reaction?</em>
Explanation:
The coupling of ATP hydrolysis which is a thermodynamically favourable reaction to the phosphorylation of glucose makes it favourable. Since the two reactions constitute a sequential reaction, their standard free energy changes are additive.
For ATP hydrolysis: ATP + H₂O ---> ADP + Pi ; ΔG'° = -30.5KJ/mol
For phosphorylation of glucose: Pi + glucose⟶glucose−6−phosphate + H2O ; ΔG'° = +13.8 kJ/Mol
For the overall reaction: ATP + glucose → glucose-6-phosphate + ADP + H⁺ ; ΔG'° = 13.8 + (-30.5) kJ/mol = -16.7 kJ/mol
Therefore, ΔG'° for the coupled reaction = -16.7 kJ/mol
