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telo118 [61]
3 years ago
9

How to find rationalizing factor of class 9​

Mathematics
1 answer:
Mrrafil [7]3 years ago
8 0

Answer:

\sqrt[5]{a^{3} b^{2}c}

Step-by-step explanation:

Rationalization factor of \sqrt[5]{a^2 b^3 c^4}

= \sqrt[5]{a^{5-2} b^{5-3}c^{5-4}}\\= \sqrt[5]{a^{3} b^{2}c^{1}}\\= \sqrt[5]{a^{3} b^{2}c}\\

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The area of a square is 275 square meters and one side length is 55 meters. What is the perimeter of the square?
Aleks [24]

Answer:

220 meter

Step-by-step explanation:

According to the scenario, computation of the given data are as follows,

Area of square = 275 square meters

Side length (a) = 55 meters

We can calculate the perimeter of square by using following formula,

Perimeter of square = 4a

By putting the value, we get

Perimeter of square = 4 × 55 mt

= 220 meter

Hence, the perimeter of the square is 220 meter.

4 0
3 years ago
Find an equation of the line containing the centers of the two circles whose equations are given below.
Anna35 [415]

Answer:

<h2><em>3y+x = -5</em></h2>

Step-by-step explanation:

The general equation of a circle is expressed as x²+y²+2gx+2fy+c = 0 with centre at C (-g, -f).

Given the equation of the circles x²+y²−2x+4y+1  =0  and x²+y²+4x+2y+4  =0, to  get the centre of both circles,<em> we will compare both equations with the general form of the equation above as shown;</em>

For the circle with equation x²+y²−2x+4y+1  =0:

2gx = -2x

2g = -2

Divide both sides by 2:

2g/2 = -2/2

g = -1

Also, 2fy = 4y

2f = 4

f = 2

The centre of the circle is (-(-1), -2) = (1, -2)

For the circle with equation x²+y²+4x+2y+4  =0:

2gx = 4x

2g = 4

Divide both sides by 2:

2g/2 = 4/2

g = 2

Also, 2fy = 2y

2f = 2

f = 1

The centre of the circle is (-2, -1)

Next is to find the equation of a line containing the two centres (1, -2) and (-2.-1).

The standard equation of a line is expressed as y = mx+c where;

m is the slope

c is the intercept

Slope m = Δy/Δx = y₂-y₁/x₂-x₁

from both centres, x₁= 1, y₁= -2, x₂ = -2 and y₂ = -1

m = -1-(-2)/-2-1

m = -1+2/-3

m = -1/3

The slope of the line is -1/3

To get the intercept c, we will substitute any of the points and the slope into the equation of the line above.

Substituting the point (-2, -1) and slope of -1/3 into the equation y = mx+c

-1 = -1/3(-2)+c

-1 = 2/3+c

c = -1-2/3

c = -5/3

Finally, we will substitute m = -1/3 and c = 05/3 into the equation y = mx+c.

y = -1/3 x + (-5/3)

y = -x/3-5/3

Multiply through by 3

3y = -x-5

3y+x = -5

<em>Hence the equation of the line containing the centers of the two circles is 3y+x = -5</em>

5 0
3 years ago
Multiply. ​ 310×(−45) ​ Enter your answer as a fraction, in simplified form, in the box.
liraira [26]
<span>-13950 there you go!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!</span>
4 0
3 years ago
a triangle pyramid with an equilateral base has a side length of 10 centimeters and a surface area of 214.5 square meters. find
sweet [91]
Area of the base = 1/2 * 10 *  5sqrt3 =  25 sqrt3

Total surface area = 25 sqrt3 + 3 *  1/2 * 10 * slant height = 214.5

25 sqrt3 + 15h = 214.5
15h = 214.5 - 25 sqrt3

h =   (214.5 - 25sqrt3() / 15

=  11.41 cm to nearest hundredth
6 0
3 years ago
Please help me with these questions
Scrat [10]

3. Answer: y = 4

<u>Step-by-step explanation:</u>

Need to find the slope (m):

  \dfrac{y_2-y_1}{x_2-x_1}

  \dfrac{4 - 4}{-3-1}

= \dfrac{0}{-4}

= 0

Now input ONE of the points (1, 4) and the slope (m = 0) into the Point-Slope formula:

y - y₁ = m(x - x₁)

y - 4 = 0(x - 1)

y - 4 = 0

y      = 4

********************************************************************

4. Answer: \bold{y = \dfrac{2}{3}x + 3}

<u>Step-by-step explanation:</u>

 y - y_1 = m(x - x_1)

 y - 1 = \dfrac{2}{3}(x - (-3))

 y - 1 = \dfrac{2}{3}(x + 3)

 y - 1 = \dfrac{2}{3}x + 2

 y = \dfrac{2}{3}x + 3


3 0
3 years ago
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