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garri49 [273]
3 years ago
7

Jim & Jesse each had the same amount of money. Jim spent $58 and Jesse spent $37. Afterward, the ratio of Jim's money to Jes

se's is 1:4. How much money did each have at first?
Mathematics
1 answer:
Marina CMI [18]3 years ago
6 0
x-\ money\ that\ each\ of\ them \ had\ previously\\\\
4(x-58)=x-37\\\\
4x-232=x-37\ \ \  | subtract\ x\\\\
3x-232=-37\ \ \ | add\ 232\\\\
3x=195\ \ \ | divide\ by\ 3\\\\
x=65\\\\
Each\ of\ them\ had\ 65\$\ at\ the\ beginning.
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Does anyone know the answer?
motikmotik

Answer:

We conclude that the area of the right triangle is:

A\:=p^2-2p-3

Hence, option A is correct.          

Step-by-step explanation:

From the given right-angled triangle,

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Using the formula to determine the area of the right-angled triangle

Area of the right triangle A = 1/2 × Base × Perpendicular

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Factor 2p-6: 2(p-3)

                                             =\frac{\left(p+1\right)\times \:2\left(p-3\right)}{2}  

Divide the number: 2/2 = 1

                                              =\left(p+1\right)\left(p-3\right)

\mathrm{Apply\:FOIL\:method}:\quad \left(a+b\right)\left(c+d\right)=ac+ad+bc+bd

                                               =pp+p\left(-3\right)+1\cdot \:p+1\cdot \left(-3\right)

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Therefore, we conclude that the area of the right triangle is:

A\:=p^2-2p-3

Hence, option A is correct.                                        

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Step-by-step explanation:

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