2 years ago

Jim & Jesse each had the same amount of money. Jim spent $58 and Jesse spent $37. Afterward, the ratio of Jim's money to Jes

se's is 1:4. How much money did each have at first?

1 answer:

6 0

$x-\ money\ that\ each\ of\ them \ had\ previously\\\\
4(x-58)=x-37\\\\
4x-232=x-37\ \ \ | subtract\ x\\\\
3x-232=-37\ \ \ | add\ 232\\\\
3x=195\ \ \ | divide\ by\ 3\\\\
x=65\\\\
Each\ of\ them\ had\ 65\$\ at\ the\ beginning.$

You might be interested in

If g(x) = 3/4 x + 2, find g(-12).

scZoUnD [109]

Answer:

(-7)

Step-by-step explanation:

just plug in the number in the x place to solve

4 0

2 years ago

PLEASEEEEE HELP<br><br> f(x) = 2x^2+ 6 when f (4)

kompoz [17]

Hopefully this is right!

5 0

2 years ago

3x2=7 5x4=23 7x6=47 9x8=79 10x9=?

Mashcka [7]

$(a\times b) = (a\times b) +(b -1) = c \\ \\ 3 \times 2 = (3\times 2) +(2-1) = 6 +1=7 \\ \\ 5 \times 4 = (5\times 4) +(4-1) = 20 +3=23 \\ \\ 7 \times 6 = (7\times 6) +(6-1) = 42 +5=47 \\ \\ 9 \times 8= (9\times 8) +(8-1) = 72 +7=79 \\ \\ \\ \\ 10 \times 9 = (10\times 9) +(9-1) = 90 +8=\boxed {\bf{98}}\\\sf {10\times 9 = \boxed{\bf {98}}}$