It should be noted that from the information, the accompanying data are the caloric contents and the sugar contents of 11 high-fiber breakfast cereals.

The sugar content will be:

a. 160 calories

= 0.18x - 20.84.

= 0.18(160) - 20.84

= 7.96

b. 90 calories

= 0.18x - 20.84.

= 0.18(90) - 20.84

= -4.64

c. 175 calories

= 0.18x - 20.84.

= 0.18(175) - 20.84

= 10.66

d. 208 calories

= 0.18x - 20.84.

= 0.18(208) - 20.84

= 16.6

Therefore, the sugar contents is illustrated above.

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8 0

1 year ago

Find the area of the circle. (Take pi 22/7

Vikki [24]

Answer:

1386cm^2.

Step-by-step explanation:

radius of circle=21cm

area of circle(a)=?

we know,

A=pi r^2

=22/7×(21)^2

=1386cm^2

6 0

2 years ago

Hi, teacher I was absent these days and I didn’t understand anything about this lesson and I need help this is not count as a te

motikmotik

Given:

There are given that the cos function:

$cos210^{\circ}=-\frac{\sqrt{3}}{2}$

Explanation:

To find the value, first, we need to use the half-angle formula:

So,

From the half-angle formula:

$cos(\frac{\theta}{2})=\pm\sqrt{\frac{1+cos\theta}{2}}$

Then,

Since 105 degrees is the 2nd quadrant so cosine is negative

Then,

By the formula:

$\begin{gathered} cos(105^{\circ})=cos(\frac{210^{\circ}}{2}) \\ =-\sqrt{\frac{1+cos(210)}{2}} \end{gathered}$

Then,

Put the value of cos210 degrees into the above function:

So,

$\begin{gathered} cos(105^{\circ})=-\sqrt{\frac{1+cos(210)}{2}} \\ cos(105^{\operatorname{\circ}})=-\sqrt{\frac{1-\frac{\sqrt{3}}{2}}{2}} \\ cos(105^{\circ})=-\sqrt{\frac{2-\sqrt{3}}{4}} \\ cos(105^{\circ})=-\frac{\sqrt{2-\sqrt{3}}}{2} \end{gathered}$

Final answer:

Hence, the value of the cos(105) is shown below:

$cos(105^{\operatorname{\circ}})=-\frac{\sqrt{2-\sqrt{3}}}{2}$

4 0

1 year ago