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4 years ago

How to evaluate -128^5/7

Mathematics

1 answer:

zimovet [89]4 years ago

4 0

Answer:

Step-by-step explanation:-4908534052.57 and round it or however your teacher wants you to.

You might be interested in

there are 6 twenty pound boxes and 8 sixty pound boxes of produce on a truck. how many pounds of produce are on the truck

Klio2033 [76]

6 *20 = 120

8 *60 = 480

120 + 480 = 600 pounds total

6 0

4 years ago

How do you calculate a net worth statement?

marissa [1.9K]

Answer:

a. Assets - Liabilities

Step-by-step explanation:

Assets/Liabilities is a management method to minimize risk. So, it cannot be the answer.

There is no formula like "Assets + Liabilities" and "Assets x Liabilities" in accounting to calculate the net worth. Therefore, those can be eliminated.

We know that net worth is calculated by deducting all liabilities (long-term and short-term) from net assets. Therefore, option (a) is the correct answer.

8 0

3 years ago

slader Suppose that 8% of all bicycle racers use steroids, that a bicyclist who uses steroids tests positive for steroids 96% of

d1i1m1o1n [39]

Answer:

P = 0.4812

Step-by-step explanation:

First, we need to use here two expressions and then do the calculations.

The first one is the conditional probability which is:

P(B|A) = P(A∩B)/P(A) (1)

The second expression to use has relation with the Bayes's theorem which is the following:

P(D|C) = P(C|D)*P(D) / P(C|D)*P(D) + P(C|d)*P(d) (2)

Now, the expression (2) is the one that we will use to calculate the probability of a selected random bicyclist who tests positive for steroids.

So, in this case, we will call C for positive and D that is using steroids and d is the opposite of d, which means do not use steroids.

Then, the probabilities are the following:

P(D) = 8% or 0.08

P(C|D) = 96% or 0.96

P(C|d) = 9% or 0.09

P(d) = 1 - 0.08 = 0.92

With these data, let's replace in expression 2

P(D|C) = 0.96 * 0.08 /0.96 * 0.08 + 0.09*0.92

P(D|C) = 0.0768 / 0.1596

P(D|C) = 0.4812 or 48.12%

8 0

3 years ago

ANSWER ASAP PLEASE !!!

Sauron [17]

3/7 = 0.43 (approx.)
4/9 = 0.44 (approx.)

Hence, 4/9 is bigger.

6 0

3 years ago

Read 2 more answers

Of the 9-letter passwords formed by rearranging the letters AAAABBCCC (4 A's, 2 B's, and 3 C's), I select one at random. Determi

Tanya [424]

Answer:

a) 3

b) (8!/9!)-(7!/9!)

c) (1-(8!/9!))*(7!/9!)

Step-by-step explanation:

a)With 4 As ; 2Bs and 3Cs it is possible to get a palindrome if you fixed the letters C according to: (2) in the extremes of the word and the other one at the center therefore you only have palindrome in the following cases

C ( ) C ( ) C

To fill in the gaps we have 4 letters A and 2 letters B, wich we have two divide in two palindrome gaps,

AAB and BAA the palindrome is C AAB C BAA C

BAA and AAB " " is C BAA C AAB C

ABA and ABA " " is C ABA C ABA C

b) 4 A ; 2B ; 3C

We have the total number of elements 9, so the total number of possible outcomes is : 9!

Total events: 9!

if we fixed 3 C we have (the group of 3 Cs becoming one element) so the total amount of events with 3 adjacent Cs is: 7!

Therefore the probability of having 3 adjacent Cs is: 7!/9!

If we fixed only 2 Cs we have:

4 A ; 2 B ; 2C : 1C

Total number of words (events) in this case is 8! (2C becomes 1 element)

so the total numbers of events is 8! the probability in this case is 8!/9!(this value includes cases of adjacent 3 Cs previous calculated ) so this value minus the case of 3 adjacent Cs ) give us 2 adjacent C and the other no next to them

Probability (of words with 2 adjacent Cs and the other no next to them is); 8!/9! - 7!/9!

c) Probability of B apart from each other is the whole set of events minus those where 2 B are adjacent or (become 1 element)

4 A ; 2B ; 3C

Total of events 9! and events with adjacent B is 8!/9!

Therefore the probability of words with 3 adjacent Cs and 2 B separeted is

the probability of 3 adjacent Cs (7!/9!) times probability of words with no adjacent Bs wich is (1-(8!/9!))*(7!/9!)

5 0

3 years ago