Answer:
x = 9
Step-by-step explanation:
y = 2/3x - 6
If the y point is 0, then plug that number into the equation and solve for x.
0 = 2/3x - 6
Add 6 to both sides of the equation.
6 + 0 = 2/3x - 6 + 6 or 6 = 2/3x
Multiply both sides by 3.
3 x 6 = 2/3x x 3 or 18 = 2x
Divide both sides by 2
18/2 = 2x / 2 or 9 = x
The answer to number 1 is 14
Answer:
x = 15.65
y = 3.5
Step-by-step explanation:
Step 1
Find the equation for x and y
Equation for x is given as
x² = 7( 7+28) ..........Equation 1
14(14 + y) = x²........ Equation 2
Solving for Equation 1
x² = 7( 7+28)
x² = 7(35)
x² = 245
x = √245
x = 15.65
From Equation 1 , x² has been determined to be 245
Therefore we substitute 245 for y in Equation 2
14(14 + y) = x²........ Equation 2
14(14 + y) = 245
196 + 14y = 245
14y = 245 - 196
14y = 49
y = 49 ÷ 14
y = 3.5
Answer:
1250 m²
Step-by-step explanation:
Let x and y denote the sides of the rectangular research plot.
Thus, area is;
A = xy
Now, we are told that end of the plot already has an erected wall. This means we are left with 3 sides to work with.
Thus, if y is the erected wall, and we are using 100m wire for the remaining sides, it means;
2x + y = 100
Thus, y = 100 - 2x
Since A = xy
We have; A = x(100 - 2x)
A = 100x - 2x²
At maximum area, dA/dx = 0.thus;
dA/dx = 100 - 4x
-4x + 100 = 0
4x = 100
x = 100/4
x = 25
Let's confirm if it is maximum from d²A/dx²
d²A/dx² = -4. This is less than 0 and thus it's maximum.
Let's plug in 25 for x in the area equation;
A_max = 25(100 - 2(25))
A_max = 1250 m²
