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Colt1911 [192]
3 years ago
15

What is the x-coordinate of the point shown in the graph? On a coordinate plane, point A is at (negative 5, negative 7).

Mathematics
2 answers:
Alinara [238K]3 years ago
8 0
The x coordinate would be -5
worty [1.4K]3 years ago
3 0

Answer:

-5

Step-by-step explanation:

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Tom is making a rectangular garden. he decides to make the garden 30 ft long by 15 ft wide. Later, tom decides to keep the lengt
OleMash [197]

Yes.  Changing the the word problem into a function, you get 30x=y.

30 = Fixed Length

x = width

y = area

No matter what width (x) you choose, the area (y) is going to be a multiple of 30 (the fixed length) because with two numbers being multiplied, if there is a fixed number that will always be the multiple and not the multiplier.  For example, 10 multiplied by every number 1-10 is going to be a multiple of 10.

10x1=10, 10x2=20, 10x3=30, etc

So if Tom chooses any of these widths (x) 5, 10, or 15, y (the area) will be a multiple of 30.

30(5)=150

30(10)=300

30(15)=450

So as we double 5 to get 10, our outcome is doubled 150 to 300 and so forth.  Hope this helps.

7 0
3 years ago
What is the distance between (4, 7)(4,7)left parenthesis, 4, comma, 7, right parenthesis and (2, 2)(2,2)left parenthesis, 2, com
tester [92]

Answer: square root of 29

Step-by-step explanation:

Given the question :

Distance between (4, 7) and (2, 2)

Distance between two points is given by:

Distance = sqrt[(X2 - X1)² + (Y2 - Y1)²]

X1 = 4 ; Y1 = 7 ; X2 = 2 ; Y2 = 2

Distance = sqrt[(2 - 4)² + (2 - 7)²]

Distance = sqrt[(-2² + - 5²)]

= sqrt(4 + 25)

= sqrt(29)

7 0
3 years ago
I need all parts answered please!
Arisa [49]
Width = w
d)length in term of width
 w + 5
b)
2(w + w + 5) > 30
2(2w +5)>30

c)
solve
2(2w +5) > 30
4w + 10 > 30
4w > 20
  w > 5

5 0
3 years ago
Fill in the blank 9,15,24,39,63,102,165,_,432,699,1131
krok68 [10]

Answer:

The answer is 267.

Step-by-step explanation:

When you add 2 previous number, you will get the next number :

e.g

9 + 15 = 24

15 + 24 = 39

24 + 39 = 63

63 + 102 = 165

102 + 165 = <u>2</u><u>6</u><u>7</u>

165 + 267 = 432

7 0
3 years ago
In JKL and PQR, if JK PQ, KL QR, and K Q, then JKL must be congruent to PQR.
Pavlova-9 [17]

True!


Two shapes are congruent if when turning, flipping or sliding one shape it can become another. This problem is illustrated in the Figure below. So, you can see that we have two triangles ΔJKL and ΔPQR. As you can see:

  • JK=PQ
  • KL=QR
  • ∠K=∠Q

Given that two sides are equal to two other sides and one angle is equal to another one, then JL= PR. Accordingly, since all the sides are congruent, then the whole triangle JKL is congruent to PQR

8 0
3 years ago
Read 2 more answers
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