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Anastasy [175]
3 years ago
7

The radius of a circle is 6mm. What is the area of the shaded portion of the circle.

Mathematics
1 answer:
mariarad [96]3 years ago
6 0

Answer:

b) 29π mm²

Step-by-step explanation:

\frac{360}{360}  - \frac{70}{360}  =  \frac{290}{360}  \\  \\\pi \:  {r}^{2} \\  =    \frac{290}{360}  \times \pi\times 6 \times 6 \\  =  29 \: \pi  \: {mm}^{2}

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Name two numbers on the number line that are a distance of 5 away from 3
tangare [24]
8 has to be one of them
4 0
2 years ago
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Suppose that, for a set of data, the range is x and the interquartile range is y. Which statement MUST be true? A) x = y B) x ≤
Vitek1552 [10]

c i suppose the answer

3 0
3 years ago
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Kristen has 64 coins in her bank. She has $9.25 in dimes and quarters. How many dimes and quarters does she have?
Stella [2.4K]
D= # of dimes
q= # of quarters

QUANTITY EQUATION:
d + q= 64

COST EQUATION:
0.10d + 0.25q= $9.25


STEP 1:
multiply quantity equation by -0.10 to be able to eliminate the d term in step 2

(-0.10)(d + q)= (-0.10)(64)
-0.10d - 0.10q= -6.40


STEP 2:
add equation from step 1 to cost equation to eliminate the d term and solve for q

Add
0.10d + 0.25q= $9.25
-0.10d - 0.10q= -6.40

0.15q= 2.85
divide both sides by 0.15

q= 19 quarters


STEP 3:
substitute q value in step 2 into either original equation to find d value

d + q= 64

d + 19= 64
subtract 19 from both sides

d= 45 dimes


CHECK:
0.10d + 0.25q= $9.25
0.10(45) + 0.25(19)= 9.25
4.50 + 4.75= 9.25
9.25= 9.25


ANSWER: There are 45 dimes and 19 quarters.

Hope this helps! :)
7 0
3 years ago
Write an equation for a parabola with x-intercepts (-4,0) and (5,0) which passes through the point (3. – 28).
Vanyuwa [196]

Answer:

y=a(x-p)(x-q)

y=a(x+2+√2)(x+2-√2)

passing through point (-1,1)

substitute

1=a(-1+2+√2)(-1+2-√2)

1=a(1+√2)(1-√2)

1=a(1-2)

1=a(-1)

a=1/(-1)

a=-1

y=-(x+[2+√2])(x+[2-√2])

y=-(x2+4x+2)

Thanks rate 5 stars

5 0
3 years ago
Which of the following are not congruence theorems for right triangles? Check all that apply.
Lera25 [3.4K]

Answer:

c) HH E)AA

Step-by-step explanation:

Two right angles can be proved congruent by LA,LL,HA,HL properties.

HH and AA are not congruence property.

Two triangles can be proved similar by AA property. All congruent triangles are similar but all similar triangles are not similar.Hence right triangles can not be proved congruent by AA property.

Among the options given Option C and E are not congruence property.

7 0
3 years ago
Read 2 more answers
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