All categories

3 years ago

Write an expression for the sequence of operations described below.

Mathematics

1 answer:

den301095 [7]3 years ago

3 0

Answer:

We conclude that:

''add 3 and the sum of 9 and v'' is algebraically represented by the expression as:

3 + 9 + v

Step-by-step explanation:

Given the statement

''add 3 and the sum of 9 and v''

Let us break down the statement

Let the number be: v

The sum of 9 and v: 9+v

Adding 3 and the sum of 9 and v will be: 3 + 9 + v

Therefore, we conclude that:

''add 3 and the sum of 9 and v'' is algebraically represented by the expression as:

3 + 9 + v

You might be interested in

If 40 men took 10 minutes to make 200 toys,how many man will take 40 minutes to make 350 toys?

Viktor [21]

40=4×10=200 toys
160=4×40=350 toys

7 0

3 years ago

Assume that BK Call Center receives 2 phone calls in one hour on average. If the department works 10 hours a day receiving the c

MrMuchimi

Using the Poisson distribution, the probabilities are given as follows:

A. 0.0888 = 8.88%.

B. 0.1354 = 13.54%.

C. 0.8646 = 86.46%.

<h3>What is the Poisson distribution?</h3>

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

The parameters are:

x is the number of successes

e = 2.71828 is the Euler number

$\mu$ is the mean in the given interval.

Item a:

10 hours, 2 calls per hour, hence the mean is given by:

$\mu = 2 \times 10 = 20$ .

The probability is P(X = 20), hence:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

$P(X = 20) = \frac{e^{-20}20^{20}}{(20)!} = 0.0888$

Item b:

1 hour, hence the mean is given by:

$\mu = 2$

The probability is P(X = 0), hence:

$P(X = x) = \frac{e^{-\mu}\mu^{x}}{(x)!}$

$P(X = 0) = \frac{e^{-2}2^{0}}{(0)!} = 0.1354$

Item c:

The probability is:

$P(X \geq 1) = 1 - P(X = 0) = 1 - 0.1354 = 0.8646$

More can be learned about the Poisson distribution at brainly.com/question/13971530

#SPJ1

5 0

2 years ago

There are 5 animals in the field. Some are horses and some are ducks. There are 14 legs in all. How many of each animal are in t

wariber [46]

Answer:

2 horses and 3 ducks

Step-by-step explanation:

2 horses*4 legs=8 legs

3 ducks*2 legs=6 legs

Add both

8+6=14 legs

4 0

3 years ago

Read 2 more answers

PLZ HELP ME ☻ <img src="https://tex.z-dn.net/?f=%5C%5B%5Cfrac%7Bxy%7D%7Bx%20%2B%20y%7D%20%3D%201%2C%20%5Cquad%20%5Cfrac%7Bxz%7D%

Yanka [14]

Answer:

$x=\frac{12}{7} \\y=\frac{12}{5} \\z=-12$

Step-by-step explanation:

Let's re-write the equations in order to get the variables as separated in independent terms as possible \:

First equation:

$\frac{xy}{x+y} =1\\xy=x+y\\1=\frac{x+y}{xy} \\1=\frac{1}{y} +\frac{1}{x}$

Second equation:

$\frac{xz}{x+z} =2\\xz=2\,(x+z)\\\frac{1}{2} =\frac{x+z}{xz} \\\frac{1}{2} =\frac{1}{z} +\frac{1}{x}$

Third equation:

$\frac{yz}{y+z} =3\\yz=3\,(y+z)\\\frac{1}{3} =\frac{y+z}{yz} \\\frac{1}{3}=\frac{1}{z} +\frac{1}{y}$

Now let's subtract term by term the reduced equation 3 from the reduced equation 1 in order to eliminate the term that contains "y":

$1=\frac{1}{y} +\frac{1}{x} \\-\\\frac{1}{3} =\frac{1}{z} +\frac{1}{y}\\\frac{2}{3} =\frac{1}{x} -\frac{1}{z}$

Combine this last expression term by term with the reduced equation 2, and solve for "x" :

$\frac{2}{3} =\frac{1}{x} -\frac{1}{z} \\+\\\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\ \\\frac{7}{6} =\frac{2}{x}\\ \\x=\frac{12}{7}$

Now we use this value for "x" back in equation 1 to solve for "y":

$1=\frac{1}{y} +\frac{1}{x} \\1=\frac{1}{y} +\frac{7}{12}\\1-\frac{7}{12}=\frac{1}{y} \\ \\\frac{1}{y} =\frac{5}{12} \\y=\frac{12}{5}$

And finally we solve for the third unknown "z":

$\frac{1}{2} =\frac{1}{z} +\frac{1}{x} \\\\\frac{1}{2} =\frac{1}{z} +\frac{7}{12} \\\\\frac{1}{z} =\frac{1}{2}-\frac{7}{12} \\\\\frac{1}{z} =-\frac{1}{12}\\z=-12$

8 0

3 years ago

PLEASE HELP I HAVE 4 MINUTES TO DO THIS WHATS 6+6

babunello [35]

Answer:

6+6=12

Step-by-step explanation:

that's the hardest question I've done today, lol

4 0

3 years ago

Read 2 more answers