<h3><u>
Answer:</u></h3><h3><u>
752 & 617</u></h3><h3 /><h3><u>
Explanation:</u></h3><h3><u>
So if Liz pays $35 each month just to use the phone, we could subtract 35 from the total bill that month to get the the total cost she spent on text messages.</u></h3><h3 /><h3><u>
March:$72.60-$35=$37.60</u></h3><h3><u>
April: $65.85-$35=$30.85</u></h3><h3 /><h3><u>
We can see that in March Liz spent $37.60 on texts in total and in April she spent $30.85 on texts in total. All we have to do is divide the amount of money she spent on texts( $37.60 & $30.85) by the cost of one text message($0.05) to get the amount of texts she sent that month.</u></h3><h3 /><h3><u>
March: $37.60/$0.05=752</u></h3><h3><u>
April: $30.85/$0.05=617</u></h3><h3 /><h3><u>
Therefore, she sent 752 texts in March and 617 texts in April.</u></h3><h3 /><h3><u>
~FrxziteTheLxoser~ I hoped I help you :)</u></h3>
<u>If i helped you please give me brainIIlest!</u>
Answer:
The correct answer is "0.0000039110".
Step-by-step explanation:
The given values are:
then,
The required probability will be:
= 
= 
= 
= 
= 
By using the table, we get
= 
Write the decimal number as a fraction
(over 1)
0.87 = 0.87 / 1
Multiplying by 1 to eliminate 2 decimal places
we multiply top and bottom by 2 10's
Numerator (N)
N = 0.87 × 10 × 10 = 87
Denominator (D)
D = 1 × 10 × 10 = 100
N / D = 87 / 100
Simplifying our fraction
= 87/100
<span>= 87/100</span>
Given:
The slope of the line is -3.
The line passes through the point (2,-2).
To find:
The point-slope form of the line.
Solution:
Point slope form: If a line passes through the point 
with slope m, then the point-slope form of the line is:
The slope of the line is -3 and it passes through the point (2,-2). So, the point-slope form of the line is:
Therefore, the required point slope form of the given line is .
Answer:
The area of the garden is 
Step-by-step explanation:
<u>Area of a Square</u>
Given a square of a side length of x, the area is calculated as:
There is a square garden area of a side length of x=50 feet. The area is:
Inside of it, there is another square area for a fountain display of a side length of 12 feet. The area is:
The area of the garden is the difference between A2 and A1:
