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3 years ago

Simplify the polynomial-

1 answer:

5 0

The answer is:

5f^2+11f-2

Explanation: All you would have to do is combine the like terms. For example; -3f^2 amd 8f^2 are both like terms because they both have the same variables and powers. Ignore the variables and powers for a second. Look at the coefficients. -3 and 8 are to be added since the 8 is a positive. Once you add them, the result will be 11f^2. You need to remember to add back the variable and power. It just seems easier that way. There is also another like term in the polynomial. 4f and 7f. You add those to get 11f. The last like term in the polynomial is -3 and 1. You add -3 to 1 and you get -2.

I hope this explanation made sense to you as I tried my best to explain it! :)

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Can someone help plsss!

Roman55 [17]

Well the y-intercept is +2

And the slope of the blue line is 1/2

So y=1/2x+2

Slope is rise/run (up then ((right)))

And the intercept is found where the line intercects the y line.

7 0

3 years ago

Read 2 more answers

A customer placed an order for muffins.The Baker has completed 37.5% of the order after baking 81 muffins. How many muffins did

IceJOKER [234]

81 divided by 37.5 equals 2.16, 2.16 would be equivalent to 1% so to find 100% we simbly multiply 2.16 by 100, 2.16 multiplied by 100 equates to 216, so the Baker is making 216 muffins.

If this is a word problem, put it into your own words in case of getting in trouble.

I hope this helped, have an awesome day!!

(brainliest is always appreciated)

6 0

3 years ago

There is a book sale at the libaray the price for each book is $4 which expression can be used to show how much money the librar

ASHA 777 [7]

4 x 289= the total cost

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3 years ago

A 1414-ft ladder leans against a wall at a point 55 feet above the ground. how far is the bottom of the ladder from the wall?

viva [34]

Assume ladder length is 14 ft and that the top end of the ladder is 5 feet above the ground.

Find the distance the bottom of the ladder is from the base of the wall.

Picture a right triangle with hypotenuse 14 feet and that the side opposite the angle is h. Then sin theta = h / 14, or theta = arcsin 5/14. theta is

0.365 radian. Then the dist. of the bot. of the lad. from the base of the wall is

14cos theta = 14cos 0.365 rad = 13.08 feet. This does not seem reasonable; the ladder would fall if it were already that close to the ground.

Ensure that y ou have copied this problem accurately from the original.

7 0

3 years ago

Alex wants to fence in an area for a dog park. He has plotted three sides of the fenced area at the points E (1, 5), F (3, 5), a

hram777 [196]

Answer:

$(1,1)$

Step-by-step explanation:

Given: E, F, G, H denote the three coordinates of the area fenced

To find: coordinates of point H

Solution:

According to distance formula,

length of side joining points $(x_1,y_1)\,,\,(x_2,y_2)$ is equal to $\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

So,

$EF=\sqrt{(3-1)^2+(5-5)^2}=2\,\,units\\FG=\sqrt{(6-3)^2+(1-5)^2}=\sqrt{9+16}=5\,\,units\\GH=\sqrt{(x-6)^2+(y-1)^2}\\EH=\sqrt{(x-1)^2+(y-5)^2}$

Perimeter of a figure is the length of its outline.

$EF+FG+GH+EH=16\\2+5+\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=16-2-5\\\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9$

Put $(x,y)=(1,1)$

$\sqrt{(1-6)^2+(1-1)^2}+\sqrt{(1-1)^2+(1-5)^2}=9\\\sqrt{25}+\sqrt{16}=9\\5+4=9\\9=9$

This is true.

So, the point $(1,1)$ satisfies the equation $\sqrt{(x-6)^2+(y-1)^2}+\sqrt{(x-1)^2+(y-5)^2}=9$

So, point H is $(1,1)$ .

7 0

3 years ago