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3 years ago

Simplify the polynomial-

1 answer:

5 0

The answer is:

5f^2+11f-2

Explanation: All you would have to do is combine the like terms. For example; -3f^2 amd 8f^2 are both like terms because they both have the same variables and powers. Ignore the variables and powers for a second. Look at the coefficients. -3 and 8 are to be added since the 8 is a positive. Once you add them, the result will be 11f^2. You need to remember to add back the variable and power. It just seems easier that way. There is also another like term in the polynomial. 4f and 7f. You add those to get 11f. The last like term in the polynomial is -3 and 1. You add -3 to 1 and you get -2.

I hope this explanation made sense to you as I tried my best to explain it! :)

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suppose our school is having a talent show to raise money for new music supplies .you estimate that 200 students and 150 adults

solong [7]

Maybe something like:
200s + 105a + 200 = 1,000
You can use x and y instead of s for student and a for adult.
Are the adults and students charged the same? If so then:
200x + 105x + 200 = 1,000

5 0

3 years ago

Read 2 more answers

Simplify (12y^7/18y^-3) assume Y=0

iren2701 [21]

$\dfrac{12y^7}{18y^{-3}} = \dfrac{2y^{7+3}}{3} = \dfrac{2y^{10}}{3} = \dfrac{2}{3}y^{10}$

3 0

3 years ago

Question 2(Multiple Choice Worth 1 points) (06.01) Solve 2x + 5y = −13 3x − 4y = −8 (4, 1) (−4, 1) (4, −1) (−4, −1)

dlinn [17]

ANSWER

The solution is
$(-4,-1)$

EXPLANATION

The given equations are:

$2x + 5y = - 13...(1)$

and

$3x - 4y = - 8...(2)$

We multiply equation 1 by 3 to get,

$6x + 15y = - 39...(3)$

We multiply equation 2 also by 2 to get,

$6x - 8y = - 16...(4)$

We subtract equation 4 from equation 3 to get,

$23y = - 23$
This implies that,

$y = - 1$

We put this value of y into any of the equations say equation 2

$3x - 4( - 1) = - 8$
Simplify

$3x + 4 = - 8$
Group like terms
$3x = - 8 - 4$
Simplify,

$3x = - 12$

Divide both sides by 3 to get,

$x = - 4$

Therefore the solution is
$(-4,-1)$

The correct answer is option D.

3 0

4 years ago

Find the missing side . round the the nearest tenth

lys-0071 [83]

$S\frac{O}{H} C\frac{A}{H} T\frac{O}{A}$

$Sin=\frac{Opposite}{Hypotenuse} Cos=\frac{Adjacent}{Hypotenuse} Tan=\frac{Opposite}{Adjacent}$

7) You have the opposite. You need the adjacent.

$Tan=\frac{Opposite}{Adjacent}$

$Tan57=\frac{12}{x}$

$x=\frac{12}{Tan57}$

x = 7.79289... =

8) You have the hypotenuse. You need the Opposite.

$Sin=\frac{x}{Hypotenuse}$

$Sin37=\frac{x}{13}$

x = sin37 × 13

x = 7.8235... =

9) You have the hypotenuse. You need the opposite.

$Sin=\frac{x}{Hypotenuse}$

$Sin59=\frac{x}{11}$

x = sin59 × 11

x = 9.4288.... =

10) You have the hypotenuse. You need the opposite.

$Sin=\frac{x}{Hypotenuse}$

$Sin53=\frac{x}{11}$

x = sin53 × 11

x = 8.7459.... =

7 0

3 years ago

Find the inverse g(x)=x/5-6

STALIN [3.7K]

Interpreted: $g(x) = \frac{x}{5} - 6$
Let $y = g(x)$
$y = \frac{x}{5} - 6$
$x = \frac{y}{5} - 6$ (Interchange the x and y-values)

$\frac{y}{5} = x + 6$ (Solve for y)
$y = 5(x + 6)$

$\therefore g^{-1}(x) = 5(x + 6)$

4 0

3 years ago