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3 years ago

Jane cuts a foam block along the red line. When she looks at the newly

Mathematics

1 answer:

alexira [117]3 years ago

4 0

I believe the answer is A

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How do you write (6)^-2 without exponents?

m_a_m_a [10]

(6)^-2 Is equivalent to 1/36

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3 years ago

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Factor out 3^2 ^3−18^2 ^4

34kurt

The factor of three is six factor of two is to 3 is three factor of two is 22 is four and poster of four is 22 Answer

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2 years ago

Which of these is the statement of the zero product rule?

anyanavicka [17]

Answer:

if a·b=0, then either a=0 or b=0, or both

Step-by-step explanation:

just answered it on apex :)

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2 years ago

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Find an equation of the sphere that passes through the origin and whose center is (-2, 2, 3). Be sure that your formula is monic

Andrei [34K]

Answer:

$\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}$

Step-by-step explanation:

Given the center of sphere is: (-2, 2, 3)

Passes through the origin i.e. (0, 0, 0)

To find:

The equation of the sphere ?

Solution:

First of all, let us have a look at the equation of a sphere:

$(x-a)^2+(y-b)^2+(z-c)^2=r^2$

Where ( $x,y,z$ ) are the points on sphere.

$(a, b, c)$ is the center of the sphere and

$r$ is the radius of the sphere.

Radius of the sphere is nothing but the distance between any point on the sphere and the center.

We are given both the points, so we can use distance formula to find the radius of the given sphere:

$D = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2+(z_2-z_1)^2}$

Here,

$x_1 =0 \\y_1 =0 \\z_1 =0 \\x_2 =-2 \\y_2 =2 \\z_2 =3$

So, Radius is:

$r = \sqrt{(-2-0)^2+(2-0)^2+(3-0)^2}\\\Rightarrow r = \sqrt{4+4+9} = \sqrt{17}$

Therefore the equation of the sphere is:

$(x-(-2))^2+(y-2)^2+(z-2)^2=(\sqrt{17})^2\\\bold{(x+2))^2+(y-2)^2+(z-2)^2=17}$

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3 years ago

If a figure is cube, then it has eight vertices

lesya692 [45]

Yes a cube has eight vertices

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3 years ago