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WARRIOR [948]
3 years ago
7

Laxmi's father is 49 years old. He is 4 years older than three times Laxmi's age. What is Laxmi's age?​

Mathematics
2 answers:
bazaltina [42]3 years ago
7 0

Answer:

15

Step-by-step explanation:

49-4years= 45/ 3= 15

Laxmi is 15

lesya692 [45]3 years ago
6 0

Answer:

Laxmi's age = 15

Step-by-step explanation:

Let's note down the data given in form of variables.

Laxmi's age = x

Laxmi's father's age = 3x + 4

                                 = 49

Let us solve the equation for Laxmi's father's age.

3x + 4 = 49

      3x = 49 - 4

      3x = 45

         x = 45 / 3

         x = 15

Hope it helped you!!

If you liked it, please mark as Brainliest..

Regards.

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Evgesh-ka [11]

Answer:

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Step-by-step explanation:

Did it in my head but generally first parentheses so -1 times by -5 is 5... still there so multiply 5 by -4p, after that no more simplifying to be done as you cant combine or simplify a number with a variable to one that doesn't have a variable.

7 0
3 years ago
Kelly earns 15% more than her sister, and together they earn $999.75. How much does Kelly earn per week?
valina [46]

Answer:

534. 75

Step-by-step explanation:

let the income of kellys sister be x

kellys income=x+15% of x

=23x over 20

x+23x/20=999. 75

or, x=465

kellys income=23×465/20

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5 0
4 years ago
A man invests his savings in two accounts, one paying 6% and the other paying 10% simple interest per year. He puts twice as muc
Masteriza [31]

Let x represent amount invested in the higher-yielding account.

We have been given that a man puts twice as much in the lower-yielding account because it is less risky. So amount invested in the lower-yielding account would be 2x.

We are also told that his annual interest is $6600 dollars. We know that annual interest for one year will be principal amount times interest rate.

I=Prt, where,

I = Amount of interest,

P = Principal amount,

r = Annual interest rate in decimal form,

t = Time in years.

We are told that interest rates are 6% and 10%.

6\%=\frac{6}{100}=0.06

10\%=\frac{10}{100}=0.10

Amount of interest earned from lower-yielding account: 2x(0.06)=0.12x.

Amount of interest earned from higher-yielding account: x(0.10)=0.10x.

0.12x+0.10x=6600

Let us solve for x.

0.22x=6600

\frac{0.22x}{0.22}=\frac{6600}{0.22}

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Therefore, the man invested $30,000 at 10%.

Amount invested in the lower-yielding account would be 2x\Rightarrow 2(30,000)=60,000.

Therefore, the man invested $60,000 at 6%.

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Answer:

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Step-by-step explanation:

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4 0
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