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3 years ago

Write in scientific notation. 0.000000459

Mathematics

1 answer:

-BARSIC- [3]3 years ago

4 0

Answer:

4.59* $10^{-7}$

Step-by-step explanation:

We need to move the decimal so there is only one zero to the left of the decimal point. Since the decimal is being moved to the right, it is a negative exponent.

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Find measure of angle if it is 20 more than 4 times its supplement

xenn [34]

Hello!

Supplementary angles add up to 180. This gives us the system of equations below.

a+b=180

b= 4a+20

Now we plug our b value into the first equation and solve for a.

a+4a+20=180

We combine like terms.

5a+20=180

We subtract 20 from both sides.

5a=160

We divide both sides by 5.

a=32

Now we want to find our angle b. We can plug our a value into the equation.

b=4(32)+20

128+20=148

Therefore, our angle measure is 148°.

I hope this helps!

7 0

3 years ago

75y^3+100y^2-3y-4=0

sweet [91]

Move all terms to the left side and set equal to zero. Then set each factor equal zero.
y = -4/3, 1/5, 1/5

7 0

3 years ago

What is this answer?

shusha [124]

Answer:

Step-by-step explanation:

Because I did this already

4 0

3 years ago

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Which two transformations are applied to pentagon ABCDE to create A'B'C'D'E'?

vekshin1

The answer is C. I need a total of 20 characters so heres a smiley face:)

6 0

4 years ago

Assume that the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder. Based on this assumption,

kompoz [17]

If the flask shown in the diagram can be modeled as a combination of a sphere and a cylinder, then its volume is

$V_{flask}=V_{sphere}+V_{cylinder}.$

Use following formulas to determine volumes of sphere and cylinder:

$V_{sphere}=\dfrac{4}{3}\pi R^3,\\ \\V_{cylinder}=\pi r^2h,$

wher R is sphere's radius, r - radius of cylinder's base and h - height of cylinder.

Then

$V_{sphere}=\dfrac{4}{3}\pi R^3=\dfrac{4}{3}\pi \left(\dfrac{4.5}{2}\right)^3=\dfrac{4}{3}\pi \left(\dfrac{9}{4}\right)^3=\dfrac{243\pi}{16}\approx 47.71;$
$V_{cylinder}=\pi r^2h=\pi \cdot \left(\dfrac{1}{2}\right)^2\cdot 3=\dfrac{3\pi}{4}\approx 2.36;$
$V_{flask}=V_{sphere}+V_{cylinder}\approx 47.71+2.36=50.07.$

Answer 1: correct choice is C.

If both the sphere and the cylinder are dilated by a scale factor of 2, then all dimensions of the sphere and the cylinder are dilated by a scale factor of 2. So

R'=2R, r'=2r, h'=2h.

Write the new fask volume:

$V_{\text{new flask}}=V_{\text{new sphere}}+V_{\text{new cylinder}}=\dfrac{4}{3}\pi R'^3+\pi r'^2h'=\dfrac{4}{3}\pi (2R)^3+\pi (2r)^2\cdot 2h=\dfrac{4}{3}\pi 8R^3+\pi \cdot 4r^2\cdot 2h=8\left(\dfrac{4}{3}\pi R^3+\pi r^2h\right)=8V_{flask}.$

Then

$\dfrac{V_{\text{new flask}}}{V_{\text{flask}}} =\dfrac{8}{1}=8.$

Answer 2: correct choice is D.

8 0

3 years ago

Read 2 more answers